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Rashid [163]
3 years ago
11

If x has a continuous uniform distribution on the interval (0,5), what is the 25th percentile for x?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
Given that X\sim\mathrm{Unif}(0,5), it has PDF

f_X(x)=\begin{cases}\dfrac15&\text{for }0\le x\l5\\\\0&\text{otherwise}\end{cases}

and thus CDF

F_X(x)=\mathbb P(X\le x)=\begin{cases}0&\text{for }x

The 25th percentile is the value X=k such that \mathbb P(X\le k)=0.25. We have

\mathbb P(X\le k)=\dfrac k5=0.25\implies k=1.25
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Which is greater, 35% of 60 or 30% of 80?
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35% of 60 = (35/100)*60 = 0.35 * 60 = 21

30% of 80 = (30/100)*80 = 0.30 * 80 = 24

24 is greater than 21.

30% of 80 is greater.

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The denominator of a fraction is 4 more than the numerator if both are decreased by 3 the simplified result is 6/7 find original
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<u>Answer:</u>

The denominator of a fraction is 4 more than the numerator. The original fraction is \frac{27}{31}

<u>Solution:</u>

Given that  

Denominator of fraction is 4 more than the numerator.

Let’s say numerator of fraction be represented by variable x.

So denominator of a faction as it is four more that numerator will be x + 4

Also given if both decreased by three than simplified result is \frac{6}{7}

=>\frac{(x-3)}{((x+4)-3)}=\frac{6}{7}

Solving above equation for x

=> 7(x – 3  ) = 6 ( x + 1 )

=> 7x – 21 = 6x + 6

=> 7x – 6x = 6 + 21

=> x = 27

Numerator of fraction = x = 27

Denominator of fraction = x + 4 = 27 + 4 = 31

\text {required fraction}=\frac{\text {numerator}}{\text {denominator}}

= \frac{27}{31}

Hence the original fraction is \frac{27}{31}

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