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MA_775_DIABLO [31]
3 years ago
5

Find the equation of the line between (7,−9) and (5,6) in slope intercept form.

Mathematics
2 answers:
poizon [28]3 years ago
5 0
Set y=ax+b pass (7,-9) (5,6)
=》-9=7a+b
6=5a+b
=》2a=-15
a=-15/2
b=6-5a=6+37.5=43.5
=》y= -15/2(x)+43.5
2y+15x=87
kari74 [83]3 years ago
3 0
ANSWER: 2y = -15x + 87

SOLUTION:

Using the two point form, (y - y1) = (x2 - x1)/(y2 - y1) (x - x1)

Y +9 = 15/-2 (x - 7)

-2y - 18 = 15x - 105

2y = -15x +87
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Zanzabum

Answer:

x-intercept = (-9,0)

y-intercept = (0,27)

Step-by-step explanation:

So first we will convert 9x - 3y = -81 into slope intercept form (y=mx+b).

Subtract 9x on both sides to get -3y = -9x -81. Next divide -3 on both sides to get y = 3x + 27.

Since b is the y-intercept, in y=mx+b and 27 is in the position of b, we can already tell that 27 is the y-intercept. So we will write it as (0,27) because coordinates are supposed to be written as (x,y).

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