Since none of the options make sense with 23, I assume it was a typo, and you meant 2/3.
Let l,w and h be the length, width and height of the original prism, and l',w' and h' be the length, width and height of the new prism. We are given

Also, if we call V the original volume, and V' the volume of the new prism, we have

Substitute the expressions for l', h' and w' in the formula for V':

Im pretty sure the answer is 80%.
Answer:
x = ⅓ acos(y/7) + π/18, [-7, 7/2]
Step-by-step explanation:
y = 7 cos(3x − π/6)
Solving for x:
y/7 = cos(3x − π/6)
acos(y/7) = 3x − π/6
acos(y/7) + π/6 = 3x
x = ⅓ acos(y/7) + π/18
The domain of x is the same as the range of y.
When x = π/6:
y = 7 cos(3π/6 − π/6)
y = 7 cos(π/3)
y = 7/2
When x = 7π/18:
y = 7 cos(21π/18 − π/6)
y = 7 cos(π)
y = -7
So the domain of x as a function of y is [-7, 7/2].
Answer:
5. k=−3
6. x=4
7. n=−108
Step-by-step explanation:
5. -14k+29=71
Subtract 29 from both sides
-14k+29-29=71-29
Simplify
-14k=42
Divide both sides by -11
-14k/-14=42/-14
6. -33=19-13x
Subtract 29 from both sides
-14k+29-29=71-29
Simplify
-14k=42
Divide both sides by -14
-14k/-14=42/-14
Simplify
k=-3
7. 8+n/25=-4
Multiply both sides by 25
25(8+n)/25 = 25 (-4)
Simplify
8+n=-100
Subtract 8 from both sides
8+n-8=-100-8
Simplify
n=-108