Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;
Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;
The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
Answer:
The answer is A: 5x + 10y > 30. That is, the combination of boxes must be greater than 30 since the requirement is to have more than 30 lb of nails.
Step-by-step explanation:
The worker can buy a combination of boxes, as long as the total is greater than 30 lb. Multiply 5 lb by x and add that to 10 lb times y to get the total, which must exceed 30 lb.
Answer:
106
Explanation:
3a+b2
Substitute the values for the variables:
3(14) + 2(32)
Solve:
3(14) + 2(32)
42 + 64
106
Answer:
Rs 8500
Step-by-step explanation:
For a cost price of c, the marked price is ...
marked = c +25%·c = 1.25c
After the 15% discount, the sale price will be ...
s = marked -15%·marked = 0.85·marked = (0.85)(1.25c) = 1.0625c
The profit will be the difference between the sale price s and the cost c:
p = s -c
500 = (1.0625c) -c = 0.0625c
Then the cost is ...
500/0.0625 = c = 8000
and the sale price is ...
s = c +p = 8000 +500 = 8500 . . . rupees
The selling price will be Rs 8500.
