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love history [14]
4 years ago
6

What dimensions would maximize the area of a rectangle with a perimeter of 40 centimeters

Mathematics
1 answer:
galben [10]4 years ago
3 0
Hi,
For all rectangle having a perimeter constant, the square have the maximum area.
So the rectangle is a square of 10 cm of side.
On other method:
Let assume x le length of the rectangle,(40-2*x)/2=20-x is the width
area=y=x*(20-x)
y=20x-x²
a)
y'=20-2x=0==>x=10 and y=10
b) y=-(x²-2*10*x+100)+100y=100-(x-10)² is maximum if x=10.

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1                                      (1,H)                             (1,T)

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3                                    (3,H)                             (3,T)

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5                                    (5,H)                             (5,T)

6                                    (6,H)                             (6,T)

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