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rjkz [21]
3 years ago
10

Find two consecutive positive intergers such that the square of the smaller interger is nineteen more than five times the larger

interger.
Mathematics
1 answer:
Naddika [18.5K]3 years ago
6 0

Answer:

8 and 9

Step-by-step explanation:

Let the two consecutive integers be x - 1 and x

Smaller = x-1

Largere = x

If the square of the smaller integer is nineteen more than five times the larger integer, then;

(x-1)² = 19 + 5x

Expand

x²-2x+1= 19+5x

x²-2x-5x+1-19 -0

x²-7x-18 =0

Factorize

x²-9x+2x-18 =0

x(x-9)+2(x-9) = 0

(x+2) = 0 and x - 9 = 0

x = -2 and 9

SInce x cannot be negative;

x = 9

Smaller number = 9-1

Smaller number = 8

Hence the two consecutive integers are 8 and 9

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The amount of the profit at x = -2 can not be determined because the number of the shirt can not be negative. Then the amount of the profit at x = 12 is $ 2 and at x = 17.5 is $ 35.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

A company manufactures and sells shirts.

The daily profit the company makes depends on how many shirts they sell.

The profit, in dollars, when the company sells x shirts can be found using the function f(x) = 6x − 70.

Find and interpret the given function values and determine an appropriate domain for the function.

Then at x = −2, then the profit will be

For this condition, the amount of the profit can not be determined because the number of the shirt can not be negative.

Then at x = 12, then the profit will be

f(12) = 6 × 12 − 70

f(12) = 72 − 70

f(12) = $ 2

Then at x = 17.5, then the profit will be

f(17.5) = 6 × 17.5 − 70

f(17.5) = 105− 70

f(17.5) = $ 35

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

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