All categories

4 years ago

The EFC is the amount of money that your family:

SAT

1 answer:

masya89 [10]4 years ago

4 0

Answer:

According to the FAFSA official site, “The Expected Family Contribution (EFC) is a measure of your family's financial strength, and is calculated according to a formula established by law” The EFC will be a number equivalent to a dollar amount. For example, 12000 is $12,000.

Explanation:

You might be interested in

Laughter is the best medicine achieve 3000 answers

Assoli18 [71]

Answer:

Explanation:

10.195.100.3810.195.100.3810.195.100.3810.195.100.3810.195.100.3810.195.100.38

10.195.100.3810.195.100.3810.195.100.38

10.195.100.3810.195.100.38

10.195.100.38

4 0

2 years ago

A species of mud snail was studied for five years. During this time, scientists observed the season in which they mated, the num

Doss [256]

Answer:

The answer is B.

Explanation:

"stressors as drought, famine, and lack of mates."

4 0

3 years ago

Critical thinking is important to understand because:

Hoochie [10]

B is correct. Trust yourself.

5 0

2 years ago

Read 2 more answers

Evaluate the line integral, where c is the given curve. C (x/y) ds, c: x = t3, y = t4, 1 ≤ t ≤ 4.

skelet666 [1.2K]

We have

x = t³ ===> dx/dt = 3t²

y = t⁴ ===> dy/dt = 4t³

Then with the given parameteriztion, the line integral along C of x/y is

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^3}{t^4} \sqrt{(3t^2)^2 + (4t^3)^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac1t \sqrt{9t^4 + 16t^6} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{\sqrt{t^4}}t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)$

$\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4$

$\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}$

6 0

2 years ago

Kp for the following reaction at a give temperature is 0. 263 at 1000. K: c(s) + 2 h2(g) ⇌ ch4(g) what is the total pressure (in

ratelena [41]

This problem is providing us with the reaction whereby methane is produced from solid carbon and gaseous hydrogen, as well as its Kp and asks for the total pressure at equilibrium for a specified addition of reactants. At the end, the answer turns out to be 11.7 atm.

<h3>Chemical equilibrium</h3>

In chemistry, when a chemical reaction takes place, it proceeds until a point called equilibrium, where the concentration of all the species start becoming unchanged. Thus, we can use equilibrium expressions whenever we needed pressures or concentrations at equilibrium.

In this case, for the reaction we were given, we can write the following equilibrium expression, where the solid carbon is excluded:

$Kp=\frac{p_{CH_4}}{p_{H_2}^2} =0.263$

Which can also be written in terms of the reaction extent and the initial pressure of hydrogen:

$0.263=\frac{x}{(p_{H_2}^0-2x)^2}$

Thus, we calculate the initial pressure of hydrogen with the temperature and volume of the flask:

$p_{H_2}^0=\frac{(4.50g/2.02g/mol)*0.08206\frac{atm*L}{mol*K}*1000K}{10.0L}\\ \\p_{H_2}^0=18.3atm$

Hence, we solve for x in the equilibrium expression as follows:

$0.263=\frac{x}{(18.3-2x)^2}\\\\x_1=6.64atm\\\\x_2=12.6atm$

Where the correct value is 6.64 atm because the 12.6 atm turns out into a negative pressure for hydrogen at equilibrium. Finally, we calculate the total pressure with:

$P_T=p_{CH_4}+p_{H_2}=x+18.3-2x\\\\P_T=6.64atm+18.3atm-2*6.64atm\\\\P_T=11.7atm$

Learn more about chemical equilibrium: brainly.com/question/13444482

6 0

3 years ago