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3 years ago

Find the academic calendar, and then answer: How many days after the end of the course are the final grades published?

1 answer:

4 0

Find the academic calendar, and then answer: How many days after the end of the course are the final grades published? Select one:

a. 12 days

b. 7 days

c. 14 days

d. 3 days

Answer:

7 days

Step-by-step explanation:

Take note that under standard practice and based on the information available that it would take up to 7 days after the end of a course for the final grades to be published.

Thus, the correct option is 7 days.

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It took Hannah 38 minutes to run 8 laps. write this statement as a rate.

likoan [24]

Simply divide the minutes by laps.

38 / 8 = 4.75

Hannah runs 1 lap in 4.75, or 4 3/4 minutes.

3 0

3 years ago

Read 2 more answers

HELP TIMED BRAINLY POINTS

kozerog [31]

Answer:

dude you need to show the whole answer

Step-by-step explanation:

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6 0

3 years ago

if y=x + 5 were changed to y= x+ 9 how would the graph of the new function compare with the first one

WITCHER [35]

It would shift up, that is the anwser

7 0

3 years ago

A torus is formed by rotating a circle of radius r about a line in the plane of the circle that is a distance R (> r) from th

jeyben [28]

Consider a circle with radius $r$ centered at some point $(R+r,0)$ on the $x$ -axis. This circle has equation

$(x-(R+r))^2+y^2=r^2$

Revolve the region bounded by this circle across the $y$ -axis to get a torus. Using the shell method, the volume of the resulting torus is

$\displaystyle2\pi\int_R^{R+2r}2xy\,\mathrm dx$

where $2y=\sqrt{r^2-(x-(R+r))^2}-(-\sqrt{r^2-(x-(R+r))^2})=2\sqrt{r^2-(x-(R+r))^2}$ .

So the volume is

$\displaystyle4\pi\int_R^{R+2r}x\sqrt{r^2-(x-(R+r))^2}\,\mathrm dx$

Substitute

$x-(R+r)=r\sin t\implies\mathrm dx=r\cos t\,\mathrm dt$

and the integral becomes

$\displaystyle4\pi r^2\int_{-\pi/2}^{\pi/2}(R+r+r\sin t)\cos^2t\,\mathrm dt$

Notice that $\sin t\cos^2t$ is an odd function, so the integral over $\left[-\frac\pi2,\frac\pi2\right]$ is 0. This leaves us with

$\displaystyle4\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}\cos^2t\,\mathrm dt$

Write

$\cos^2t=\dfrac{1+\cos(2t)}2$

so the volume is

$\displaystyle2\pi r^2(R+r)\int_{-\pi/2}^{\pi/2}(1+\cos(2t))\,\mathrm dt=\boxed{2\pi^2r^2(R+r)}$

6 0

2 years ago

a globe has a diameter of 24 inches. a smaller globe has a diameter of 18 inches. What is the surface are to volume ratio of the

faust18 [17]

Answer:

1 pi: 3pi

Step-by-step explanation:

Step 1: Formula of surface area and volume of sphere

Surface area of sphere = 4 x pi x r^2

Volume of sphere = 4 x pi x r^3

Step 2: Apply values in the formula

r = radius

radius = diameter/2

r=18/2 = 9

S.A = 4 x pi x 9^2

S.A = 324pi

Volume = 4 x pi x 9^3

Volume = 972pi

Step 3 : Show in ratio

Surface area : Volume

324pi : 972pi

= 1 pi: 3pi

6 0

3 years ago