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soldier1979 [14.2K]
3 years ago
6

I need help please????

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

the answer  is no

Step-by-step explanation:

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On January 2, Bering Co. disposes of a machine costing $44,000 with accumulated depreciation of $24,625. Prepare the entries to
jeyben [28]

Answer:

The accounting entry under each condition is given below.

The machine is sold for $18,250 cash

Debit Cash Asset                              $ 18,250

Debit accumulated depreciation     $ 24,625

Debit Loss on disposal                     $    1,125

Credit Machine Cost                         $ 44,000

The machine is traded in for a new machine having a $60,200 cash price. A $25,000 trade-in allowance is received, and the balance is paid in cash.

Debit New Machine Asset                $ 60,200

Debit accumulated depreciation      $ 24,625

Credit profit on disposal                    $    5,625

Credit Machine Cost                          $ 44,000

Credit Cash Asset (60,200-25,000) $ 35,200

The machine is traded in for a new machine having a $60,200 cash price. A $15,000 trade-in allowance is received,

Debit New Machine Asset                  $ 60,200

Debit accumulated depreciation        $ 24,625

Debit loss on disposal                         $   4,375

Credit Machine Cost                           $ 44,000

Credit Cash Asset (60,200-15,000)   $ 45,200

3 0
4 years ago
Suppose that you are to make a rectangular box with a square base from two different materials. The material for the top and fou
saw5 [17]

Answer:

height = 14.5 ft

width = length = 3.2 ft

Step-by-step explanation:

Let the side of the square base is a and the height of the box is h.

The material required to make the box is equal to the total surface area of the box.

Area of base = a²

Cost of square base is $ 2 per ft²

So, the cost of making base = 2a²

Area of four walls + area of top = 2 (a² + ah + ah) + a² =  3a² + 2ah

Cost of making walls and the top is $ 1 per ft²

So, the cost of making walls and the top = 1 x ( 3a² + 2ah)

Total cost of making the box = 2a² + 3a² + 2ah = 5a² + 2ah

According to the question

144 = 5a² + 2ah

h = \frac{144-5a^{2}}{2a}     .... (1)

The volume of the box is V = length x width x height

V = a x a x h

V = 72 a - 2.5 a³     from equation (1)

Differentiate both sides with respect to a.

dV/da = 72 - 7.5 a²

Put, it equal to zero for maxima and minima

7.5 a² = 72

a = 3.2 ft

Put in equation (1)

h = \frac{144-5\times 3.2\times 3.2}{2\times 3.2}

h = 14.5 ft

So, the dimensions of the box are

height = 14.5 ft

width = length = 3.2 ft

6 0
3 years ago
Which property can be used to expand the expression Negative 2 (three-fourths x + 7)?
swat32

Answer:

I don't recall if there is a term for it, most people just say distributing the 2 to each term in the bracket, -3/2x-14

Step-by-step explanation:

. -2 x 3/4x     -2 x 7 =  -3/2x-14

5 0
3 years ago
Which of the following tables represents a proportional relationship?
Art [367]

Answer:

Step-by-step explanation:

the answers c

7 0
3 years ago
Which statement is true?
lisov135 [29]
No statements are true
3 0
3 years ago
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