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34kurt
3 years ago
9

Which statement is true?

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0
No statements are true
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1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
4 years ago
Logs5(3x-2) = 1 + Logs5 (x-4)
AnnZ [28]

Answer:

57

Step-by-step explanation:

6 0
3 years ago
A person who weighs 100 pounds on the Earth weighs 16.6 lb. on the moon. Which variable is the independent variable? Explain why
vladimir2022 [97]
The weight on Earth is the independent variable. Your weight on the moon depends on how much you weigh on the earth. The more you way on earth the more you way on the moon.
4 0
4 years ago
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The quarterback is sacked for a loss of 14 yards. Represent this amount in integer.
ratelena [41]
The integer will be -14 because he loss 14 yards
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4 0
3 years ago
What is 2E*-4V*:34&gt;2+sv5
Mrac [35]

Answer:yes

Step-by-step explanation:

6 0
3 years ago
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