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Dafna11 [192]
3 years ago
9

What is the equation of the plane that contains the triangle shown in the diagram?

Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
The first equation

2x + 3y + 6z = 12
kolezko [41]3 years ago
3 0

Answer:

Option A is correct.

2x + 3y +z = 6

Step-by-step explanation:

The intercept form of the equation of plane is given by:

\frac{x}{l}+\frac{y}{m} +\frac{z}{n} =1            .....[1]

where

l is the intercept of x-axes

m is the intercept of y-axes and

n is the intercept of z-axes respectively;

From the given figure;

we have;

The intercepts of coordinates axes are;

l = 3

m = 2

n = 6

Substitute these values in the equation [1]; we have;

\frac{x}{3}+\frac{y}{2} +\frac{z}{6} =1  

Taking LCM of 3, 2 and 6 is 6

2x + 3y +z = 6

therefore, the equation of plane that contains the triangle as shown in the diagram is, 2x + 3y +z = 6

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Step-by-step explanation:

Simplifying

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Solving

16 + 2x = -12 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

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Combine like terms: 2x + -3x = -1x

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Combine like terms: 3x + -3x = 0

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Step-by-step explanation:

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