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3 years ago

Helpppppppppp give bralienst

Mathematics

2 answers:

rodikova [14]3 years ago

7 0

Answer:

Step-by-step explanation:

16/16=1

Hope this helps, if you have any questions, feel free to ask

Have a good day! :)

alina1380 [7]3 years ago

6 0

Answer:

Hope that helps.

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What is the perimeter of the triangle

nevsk [136]

Answer:

There’s no image, but to find the perimeter of the triangle just add up the totals of each side.

Step-by-step explanation:

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2 years ago

In a certain survey of 1,024 adults, 83% reported having more than one television at home. Find the actual number of responden

irina [24]

Answer:

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Step-by-step explanation:

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2 years ago

Which phrase describes an unknown or changeable quantity?

Artist 52 [7]

B i think that because there’s no quantity

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2 years ago

Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

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2 years ago

Form the quadratic equation whose one root is 2 + 2^(1/2)

Oksanka [162]

9514 1404 393

Answer:

x^2 -4x +2 = 0

Step-by-step explanation:

The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...

(x -2-√2)(x -2+√2) = 0

Expanding this, we get ...

(x -2)^2 -(√2)^2 = 0

x^2 -4x +4 -2 = 0

x^2 -4x +2 = 0 . . . . the equation you're looking for

4 0

2 years ago