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kotegsom [21]
3 years ago
9

X(x-5)+3(x-5) please I really need help with this

Mathematics
1 answer:
Maru [420]3 years ago
5 0
Is this the answer you were looking for? If not I’m sorry

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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.
Anastaziya [24]

Answer:

C) 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins

Step-by-step explanation:

Your goal is to find out how many of each item will equate to 21 dollars. Your function is as follows:

1.5x+3y+1.5z=21

Where x, y, z are peanuts, almonds, raisins respectively (in that order). 21 is the total cost of the mixture.

All you have to do is start plugging in the variables given in the answer choices.

<u>A) Peanuts (x) = 3, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

1.5x+3y+1.5z=21\\1.5(3)+3(6)+1.5(2)=21\\4.5+12+3=21\\\\19.5 \neq 21

A doesn't equal 21. On to the next one.

<u>B) Peanuts (x) = 8, Almonds (y) = 6, Raisins (z) = 2</u>

Everywhere you see x,y,z, you replace with their value.

1.5x+3y+1.5z=21\\1.5(8)+3(1)+1.5(2)=21\\12+3+3=21\\\\18 \neq 21

B also doesn't equal 21. On to the next one...

<u>C) Peanuts (x) = 6, Almonds (y) = 3, Raisins (z) = 2</u>

Everywhere you see x,y,z you replace with their value.

1.5x+3y+1.5z=21\\1.5(6)+3(3)+1.5(2)=21\\9+9+3=21\\\\\\21 = 21

Both sides of the equation equal 21 which means C is our answer.

7 0
3 years ago
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

8 0
3 years ago
Need help number 13 <br><br>4 grade answer
Vedmedyk [2.9K]
I dont see anything maybe you forgot to add the answer'

8 0
3 years ago
Joe solved this problem on a math test. 5/6 - 1/4 = 7/8
Travka [436]

Answer:

This is incorrect, the correct answer is 7/12

Step-by-step explanation:

5 0
3 years ago
You are buying a new internet service. The service costs $75 per month. In the equation below, d is the
AVprozaik [17]

Answer:

The total number of dollars you pay:  Dependent

The time in months you keep your service:  Independent

6 0
3 years ago
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