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3 years ago

Joe solved this problem on a math test. 5/6 - 1/4 = 7/8

Mathematics

1 answer:

Travka [436]3 years ago

5 0

Answer:

This is incorrect, the correct answer is 7/12

Step-by-step explanation:

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A soccer player ran 180.48 miles in 70.5 days to stay fit. How many miles will he run in 9 days

cluponka [151]

Answer:

23.04 miles

Step-by-step explanation:

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3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST

SOVA2 [1]

Answer:

65 degrees

Step-by-step explanation:

The angles will sum up to 360, just do 360 - all known angles

360 - 90 - 128 - 77 = 65

3 0

3 years ago

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A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

7 1/6 = 5 2/5 + p<br><br> p = ???

Crank

$\huge\textbf{Hey there!}$

$\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}$

$\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}$

$\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}$

$\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}$

$\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}$

$\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}$

$\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}$

$\large\textsf{SIMPLIFY IT!}$

$\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}$

$\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark$

$\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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2 years ago

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Evaluate the following expression. 6^-1

Ugo [173]

Do you mean 1/6 as the evaluation?

8 0

3 years ago

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