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devlian [24]
3 years ago
8

$325 tent; 15% Discount

Mathematics
2 answers:
beks73 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

48.75

Natasha2012 [34]3 years ago
7 0
85% of 325 is $276.25. and if you take 15% off of the price, your only left with 85%. Hope that helps.
You might be interested in
Carmen is 62.5 inches tall. How many centimeters tall is she?<br> 1 inch<br> =<br> 2.54 cm
sattari [20]

Answer:

158.75

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How fo you solve the quadratic equation by factoring 3x^2=5x
qaws [65]
Good morning ^ _ ^


3x² = 5x
3x² - 5x = 0
From that part we can factorize
x(3x - 5) = 0
Set factors equal to 0
x = 0 or 3x - 5 = 0
x =0 or 3x = 0 + 5
x = 0 or 3x = 5
x = 0 or x = 5/3

The final answer is : X = 0 or X = 5/3


A+ Guaranteed! 

8 0
3 years ago
UCF believes that the average time someone spends in the gym is 56 minutes. The university statistician takes a random sample of
11111nata11111 [884]

Answer:

We conclude that the average time someone spends in the gym is different from 56 minutes.

Step-by-step explanation:

We are given that UCF believes that the average time someone spends in the gym is 56 minutes.

The university statistician takes a random sample of 32 gym goers and finds the average time of the sample was 50 minutes. Assume it is known the standard deviation of time all people spend in the gym is 8 minutes.

<u><em>Let </em></u>\mu<u><em> = population average time someone spends in the gym</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu = 56 minutes   {means that the average time someone spends in the gym is 56 minutes}

<u>Alternate Hypothesis</u>, H_A : \mu\neq 56 minutes   {means that the average time someone spends in the gym is different from 56 minutes}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average time someone takes in the gym = 50 min

              \sigma = population standard deviation = 8 minutes

              n = sample of gym goers = 32

So, <em><u>test statistics</u></em>  =   \frac{50-56}{\frac{8}{\sqrt{32} } }

                               =  -4.243

<em>Since in the question we are not given the level of significance so we assume it to b 5%. Now at 5% significance level, the z table gives critical value between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lie within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.</em>

Therefore, we conclude that the average time someone spends in the gym is different from 56 minutes.

4 0
3 years ago
Find the average rate of change of each function over the interval [0, 2]. Match each representation with its respective average
marishachu [46]
Average rate of change over interval [a,b]: r=[f(b)-f(a)]/(b-a)
In this case the interval is [0,2], then a=0, b=2
r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
r=4

2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
r=(0+10)/2
r=(10)/2
r=5

3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
g(0)=2
r=(6-2)/2
r=(4)/2
r=2

4) Fourth function: j(x)
r=[j(2)-j(0)]/2
From the table:
x=2→j(2)=-8
x=0→j(0)=4
r=(-8-4)/2
r=(-12)/2
r=-6

Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
8 0
4 years ago
Which set of ordered pairs does not represent a function?
MArishka [77]
B does not represent a function
3 0
4 years ago
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