What is i84?<br> A. i<br> B. -,<br> C. 1<br> O D.-1

Suppose that for a particular family of T-distributions that t2 has 2 degrees of freedom (df) and t9 has 9 degrees of freedom. W

aksik [14]

tdf will approach z.

Suppose that for a particular family of T-distributions that t2 has 2 degrees of freedom (df) and t9 has 9 degrees of freedom.

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7 0

2 years ago

Chlorofluorocarbons (CFCs) were used as propellants in spray cans until their buildup in the atmosphere started destroying the o

melamori03 [73]

Answer:

a) C(2000)=1915

C(2014)=1915

b) $C'(2000)=-\frac{275}{14}$

$C'(2014)=-\frac{275}{14}$

c) $C(t)=-\frac{275}{14}t+\frac{288405}{7}$

d) t=2021

e) too early

Step-by-step explanation:

a)

Since C(t) is the concentration of CFCs in ppt in year t, all we need to do to solve this part is determine what the concentration of CFCs is in years 2000 and 2014. Luckily for us, the problem already gives us those values, so:

C(2000)=1915 concentration in year 2000

C(2014)=1915 concentration in year 2014

b)

By definition, the derivative of a function at a given point is interpreted as the slope of the tangent line to the point of interest, so in order to find this answer, we need to find the slope of the line. Since the problem specifies that the behavior is linear, this means that the slope will always be the same no matter the year, so we get:

$m=C'(t)=\frac{C'(t_{2})-C'(t_{1})}{t_2-t_1}$

so:

$C'(t)=\frac{1640-1915}{2014-2000}=-\frac{275}{14}\approx -19.64$

therefore:

$C'(2000)=-\frac{275}{14}$

$C'(2014)=-\frac{275}{14}$

c)

Since the behavior is linear, we can calculate it with the point-slope form of the line which is:

$y-y_{1}=m(x-x_{1})$

in this case:

$C(t)-C(t_1)=C'(t)(t-t_{1})$

so we get:

$C(t)-1915=-\frac{275}{14}(t-2000)$

and we can now solve for C(t) so we get:

$C(t)=-\frac{275}{14}t+\frac{275000}{t}+1915$

for a final answer of:

$C(t)=-\frac{275}{14}t+\frac{288405}{7}$

d)

So next we solve the equation for C(t)=1500 so we get:

$1500=-\frac{275}{14}t+\frac{288405}{7}$

$1500-\frac{288405}{7}=-\frac{275}{14}t$

$-\frac{277905}{7}=-\frac{275}{14}t$

$t=2021 \frac{7}{55}$

so we will reach that concentration level at the year 2021 approximately.

e)

Since the second derivative of the concentration function is greater than zero, this means that the original function might be a function in the form: .

This means that the decrease of the concentration levels is slower than that of a linear equation. So the projected date will be too early than the real date.

8 0

3 years ago

2, 6, 10, 14, ...

8090 [49]

The sequence can be represented by $2 + 4x$ , where $x$ is a whole number( $x \geq 0$ and $x$ is an integer). By this, we should be able to plug in some whole number x and be able to get these values if they are in the sequence. To test this, let's set these numbers equal to $2 + 4x$ and confirm that there is a whole number x which equals the values selected.

$2 + 4x = 90 \Rightarrow 4x = 88 \Rightarrow x = 22 \, \checkmark$

$2 + 4x = 150 \Rightarrow 4x = 148 \Rightarrow x = 37 \, \checkmark$

$2 + 4x = 160 \Rightarrow 4x = 158 \Rightarrow x = 39.5$

When trying 160 with our equation, we find that x doesn't equal a whole number, thus our answer is C, or 160. To confirm our answer, we can test 170 and 210 and confirm that they both give us a value for x which is a whole number.

$2 + 4x = 170 \Rightarrow 4x = 168 \Rightarrow x = 42 \, \checkmark$

$2 + 4x = 210 \Rightarrow 4x = 208 \Rightarrow x = 52 \, \checkmark$

6 0

3 years ago

What do the following two equations represent?

klio [65]

Answer:

perpendicular lines

Step-by-step explanation:

when the two equation are written in slope intercept form:

y = -4x -7

y = 1/4x -2

the slopes are opposite reciprocals which means they are perpendicular

8 0

3 years ago

Solve: k/3+4-5k=-2k (LOOK AT PICTURE)

stepan [7]

The answer for this is k=3/2

3 0

3 years ago

What is i84? A. i B. -, C. 1 O D.-1