Option C
Math teacher would need to buy 130 prizes
<em><u>Solution:</u></em>
Given that,
Math teacher currently has 109 students and the box has 88 prizes in it
The math teacher likes to keep at least twice as many prizes in the box as she has students
So, she wants the number of prizes to be twice the number of students
Therefore,
number of prizes = 2 x 109 students
number of prizes = 2 x 109 = 218 prizes
The box has 88 prizes in it
Therefore, number of prizes she would need to buy is:
⇒ 218 - 88 = 130
Thus she would need to buy 130 prizes
Answer:
??? I don't quite understand pls explain better
Step-by-step explanation:
Answer:
19.0681
Step-by-step explanation:
Given in the question that,
angle from ted to the dog = 60° with the ground
height of ted from the ground = 16ft
To find,
distance between dog and the door of ted's building
Considering the scenario make a right angle triangle:
<h3>By using pythagorus theorem:</h3>
Tan 40 = opposite / adjacent
Tan 40 = height / distance between dog and the door
Tan 40 = 16ft / x
x = 16 / tan40
x = 19.068057
x ≈ 19.0681 (nearest to thousand)
So, the dog need to walk 19.0681ft to reach the open door directly below Ted.
Complete question:
y = 2x² + 2x - 3
x = -2 -1 0 1 2
Answer:
<u>Complete table of values</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Step-by-step explanation:
Given;
y = 2x² + 2x - 3
To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.
when, x = -2
y = 2(-2)² + 2(-2) - 3
y = 8 - 4 - 3
y = 1
when x = -1
y = 2(-1)² + 2(-1) - 3
y = 2 - 2 - 3
y = -3
when x = 0
y = 2(0)² + 2(0) - 3
y = 0 - 0 - 3
y = -3
when x = 1
y = 2(1)² + 2(1) - 3
y = 2 + 2 - 3
y = 1
when x = 2
y = 2(2)² + 2(2) - 3
y = 8 + 4 - 3
y = 9
<u>Complete table</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Answer:
400 m/s
Step-by-step explanation:
u=0 m/s
t=20 s
a=20 m/s²
v=u+at
=0+20×20
=400 m/s
