3 years ago

Which is a solution to 2x + 1 = 21?

Mathematics

1 answer:

Bezzdna [24]3 years ago

4 0

Answer:

x = 10 is your answer

- Explain -

Step 1: subtract 1 from both sides (subtraction of equality)

which will give us:

2x = 21 - 1

which equals to

2x = 20

Step 2: Divide both sides by 2

which is

2x/2 = 20/2

2/2 = 1 and 20/2 = 10

Therefore the answer is x = 10

You might be interested in

You flip a coin.

SVEN [57.7K]

50 percent is the probability

7 0

3 years ago

Read 2 more answers

A = 1/2ha +1/2hb solve for b

meriva

Answer:

A=1+1+2ha+2hb

A=2+2ha+2hb

A=2ha+2+2hb

A=4ha+2hb

4 = 4

A=½

3 0

3 years ago

What is f(g(x)) for x > 5?

mel-nik [20]

Answer:

$\large\boxed{B.\ 4x^2-41x+105}$

Step-by-step explanation:

$f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105$