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kobusy [5.1K]
3 years ago
12

A person invests 9000 dollars in a bank. The bank pays 6% interest compounded monthly. To the nearest tenth of a year, how long

must the person leave the money in the bank until it reaches 14000 dollars?
Mathematics
1 answer:
il63 [147K]3 years ago
3 0

Answer:

7.4\ years  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=?\ years\\ P=\$9,000\\ r=0.06\\n=12\\ A=\$14,000  

substitute in the formula above  

14,000=9,000(1+\frac{0.06}{12})^{12t}  

(14/9)=(1.005)^{12t}  

Apply log both sides

log(14/9)=(12t)log(1.005)  

t=log(14/9)/[(12)log(1.005)]  

t=7.4\ years  

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