If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.
<h3>How to find angles of cyclic quadrilateral?</h3>
A cyclic quadrilateral is inscribed in a circle. It has all its vertices on the circumference of the circle.
Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.
Therefore,
∠F + ∠H = 180°
∠G + ∠E = 180°
Hence, if we moved ∠G to a different spot on the circle, angle FGH would change but angle FEH will also change to make the two opposite angles supplementary.
Therefore, Felix was wrong.
learn more on cyclic quadrilateral here: brainly.com/question/21208662
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UW is always equal to 9x-9 or 9(x-1) whenever x is a real number. By adding in x, we can get the value.
For example, if x was 4, we add in x, giving us 9*4-9=36-9=27 units or
9(4-1)=9(3)=27 units
Hoped this helped in time!
To compare the two classes, the Coefficient of Variation (COV) can be used.
The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)
For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)
The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.
Answer:
We use Baye's theorem: P(A)P(B|A) = P(B)P(A|B)
with (A) being defective and
(B) marked as defective
we have to find P(B) = P(A).P(B|A) + P(¬A)P(B|¬A). .......eq(2)
Since P(A) = 0.1 and P(B|A)=0.9,
P(¬A) = 1 - P(A) = 1 - 0.1 = 0.9
and
P(B|A¬) = 1 - P(¬B|¬A) = 1 - 0.85 = 0.15
put these values in eq(2)
P(B) = (0.1 × 0.9) + (0.9 × 0.15)
= 0.225 put this in eq(1) and solve for P(B)
P(B) = 0.4
Answer:
I believe this is pathgorean theorem, which I did at the beginning of alegbra last year. It is basically finding the missing side of a triangle. (Trust me some of the easiest stuff you do all year) Below are my notes from last year. I hope it helps! Good Luck!!!
Step-by-step explanation:
Given two sides
If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:
a² + b² = c²
if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:
a = √(c² - b²)
if leg b is unknown, then
b = √(c² - a²)
for hypotenuse c missing, the formula is
c = √(a² + b²)
