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Kobotan [32]
4 years ago
14

Need help with this math​

Mathematics
1 answer:
polet [3.4K]4 years ago
3 0

Answer:

N = Q/3  -  V

Step-by-step explanation:

Q = 2N + 3V solve for N

Subtract 3V from both sides

Q - 3V = 3N

Divide both sides by 3

(Q - 3V)/3 = N

Q/3 - V = N

or

N = Q/3  -  V

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The answer is:  [C]:  "no solution" .
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              2 * { 3y = 3/2 x + 6 } ;  to get:  6y = 3x + 12 

           
Given:  1/2 y –1/4 x = 3 ;  Multiply EACH SIDE by "4" ; to get rid of the fraction ;


            4 * { 1/2 y – 1/4 x = 3 } ;  to get:  2y – x = 12 ;
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So we have:

6y = 3x + 12 ;

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Multiply BOTH side of the "second equation" by "-1" ;

-1 * { 2y – x = 12 } ; 

to get :   x – 2y = -12  ;  

Now, add "2y" to each side of the equation;  
 to isolate "x" on one side of the equation; & to solve for "x" ; 

  x – 2y + 2y = -12 + 2y ; 

to get:  x = 2y – 12 ; 

Now, consider the "first equation" ; 

6y = 3x + 12 ; 
 
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to get:  2y = x + 4 ; 

Divide EACH SIDE of the equation by "2" ; 

2y/ 2  = ( x + 4) /2 ; 

to get:  y = (x + 4) / 2 ;
 
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 y = [ (2y – 12)] + 4)] / 2 ; 

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The answer is:  [C]:  "no solution" .
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7 0
3 years ago
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3 years ago
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7nadin3 [17]

Answer:

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Oliga [24]
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6 0
3 years ago
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