Answer:
a. E(x) = 3.730
b. c = 3.8475
c. 0.4308
Step-by-step explanation:
a.
Given
0 x < 3
F(x) = (x-3)/1.13, 3 < x < 4.13
1 x > 4.13
Calculating E(x)
First, we'll calculate the pdf, f(x).
f(x) is the derivative of F(x)
So, if F(x) = (x-3)/1.13
f(x) = F'(x) = 1/1.13, 3 < x < 4.13
E(x) is the integral of xf(x)
xf(x) = x * 1/1.3 = x/1.3
Integrating x/1.3
E(x) = x²/(2*1.13)
E(x) = x²/2.26 , 3 < x < 4.13
E(x) = (4.13²-3²)/2.16
E(x) = 3.730046296296296
E(x) = 3.730 (approximated)
b.
What is the value c such that P(X < c) = 0.75
First, we'll solve F(c)
F(c) = P(x<c)
F(c) = (c-3)/1.13= 0.75
c - 3 = 1.13 * 0.75
c - 3 = 0.8475
c = 3 + 0.8475
c = 3.8475
c.
What is the probability that X falls within 0.28 minutes of its mean?
Here we'll solve for
P(3.73 - 0.28 < X < 3.73 + 0.28)
= F(3.73 + 0.28) - F(3.73 + 0.28)
= 2*0.28/1.3 = 0.430769
= 0.4308 -- Approximated
Answer:
A and C
Step-by-step explanation:
Move all terms to the left side and set equal to zero. Then set each factor equal to zero
Change each mixed fraction to improper
3 2/5 = 15/5 + 2/5 = 17/5
9 1/10 = 90/10 + 1/10 = 91/10
Find a common denominator. Multiply 2 to both numerator and denominator of 17/5
17/5(2/2) = 34/10
34/10 + 91/10 = 125/10
125/10
Simplify. Divide
125/10 = 12.5
12.5 is your answer
hope this helps
Bob's car rental company makes you pay 10 dollars per day you rent the car and a 30 dollar insurance fee
joe's car rental company makes you pay 30 dollars per day you rent the car and a 10 dollar insurance fee
how many days do you need to rent a car for the cost for renting both are the same
bob=10x+30
joe=30x+10
set each to each other
10x+30=30x+10
subtract 10x
30=20x+10
subtract 10
20=20x
divide both sides by 20
1=x
you need to rent 1 day for them to be equal
Would it be y2 ? idk im not sure but i tried
