The factorization if the given expression 128 + 2d³ is 2(64 + d³).
<h3>Factorization</h3>
128 + 2d³
There are two parameters in the expression;
The common factors between 128 and 2d³ is 2
So,
128 + 2d³
= 2(64 + d³)
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The answer your looking for is 33.3%
(it goes on a lot longer but that's just rounded to 1 decimal place)
Translation 1 unit left and rotation of 90 degrees counterclockwise
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17 one point shots and 39 two point shots were made
Solution:
Given that,
At a basketball game, a team made 56 successful shots
They were a combination of 1- and 2-point shots
Let "x" be the number of 1 point shots
Then, 56 - x is the number of two point shots
The team scored 95 points in all
Therefore,
1(number of 1 point shots) + 2(number of two point shots) = 95
x + 2(56 - x) = 95
x + 112 - 2x = 95
x = 112 - 95
x = 17
Then, number of two point shots = 56 - x = 56 - 17 = 39
Thus 17 one point shots and 39 two point shots were made