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castortr0y [4]
3 years ago
6

Help me and I give you

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0
Im pretty sure its b im soo sorry if im wrong.
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Remember if two lines are perpendicular, the product of their slopes are -1
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Hi<br> Someone that is able to do it
VARVARA [1.3K]
I think it’s b

Not for sure but it makes the most sense
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3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

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ANSWER
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EXPLANATION

If ABCD is a parallelogram, then

line AB is parallel to line DC .

This means that,

(x + 2) \degree
and

(2x - 2) \degree
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Alternate angles are congruent.

This implies that,

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2x - x = 2 + 2

This simplifies to,

x = 4

Also, if ABCD is a parallelogram then,

BC is parallel to AD. This means that,

5y - 8 = y + 24

We group like terms to get,

5y - y = 24 + 8

This simplifies to,

4y = 32

We divide both side by 4 to get,

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