Answer:
From the diagram associated with this question it can be seen that the first bounce was 1 units high, thus the second bounce is 1 / 2 = 0.5 units high and the third bounce is 0.5 / 2 = 0.25 = 1/4 units high.
Given that B represents the second bounce and C represents the first bounce, the fractions in hundredths that should be written at points B is 0.50 while at point C is 0.25
Step-by-step explanation:
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Answer:
The last graph
Step-by-step explanation:
We are given two tips for finding our graph, it has a max point and the point of the line is x = 3. Meaning that this graph must open down and should not go anything further than 3 on the y graph.
The only one that fits this proposition is the last graph. Making it correct.
Answer:
Step-by-step explanation:
- The first question's slope is 0 because it is a straight horizontal line
- The second question is undefined because it is a straight vertical line
- The third question's slope isn't able to be found with a blank line, but the line is positive because the more it travels right, it also goes up. So the slope of the third is positive
- The fourth is similar to the third as its slope cannot be calculated with a blank line, but the more it moves right, the more it moves down, meaning the slope is negative.
Answer:
Zeros of the given function are x=5 and x=-1.
Step-by-step explanation:
f(x)=x^2-4x-5
f(x)=x^2+1x-5x-5
f(x)=x(x+1)-5(x+1)
f(x)=(x-5)(x+1)
To find zeros, we need to set f(x)=0
0=(x-5)(x+1)
0=(x-5) or 0=(x+1)
0=x-5 or 0=x+1
5=x or -1=x
Hence zeros of the given function are x=5 and x=-1.
We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.
That will give the final graph as attached below:
for x=0,
f(x)=x^2-4x-5
f(0)=0^2-4(0)-5
f(0)=0-0-5
f(0)=-5
Hence first point is (0,-5)
Similarly we can find more points.
