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Andrej [43]
3 years ago
8

Given the function ƒ(x) = x 2 - 4x - 5

Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:

Zeros of the given function are x=5 and x=-1.

Step-by-step explanation:


f(x)=x^2-4x-5

f(x)=x^2+1x-5x-5

f(x)=x(x+1)-5(x+1)

f(x)=(x-5)(x+1)

To find zeros, we need to set f(x)=0

0=(x-5)(x+1)

0=(x-5) or 0=(x+1)

0=x-5 or 0=x+1

5=x or -1=x


Hence zeros of the given function are x=5 and x=-1.


We can plug some random numbers like x=0,1,2,... into given function to find few points then graph those points and join them by a curved line.

That will give the final graph as attached below:

for x=0,

f(x)=x^2-4x-5

f(0)=0^2-4(0)-5

f(0)=0-0-5

f(0)=-5

Hence first point is (0,-5)

Similarly we can find more points.


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