Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
Solute=potassium chloride, solvent=water
Answer:
There are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.
Explanation:
We can calculate the number of moles (η) of BeO as follows:
Where:
m: is the mass = 250 g
M: is the molar mass = 25.0116 g/mol
Hence, the number of moles is:
Therefore, there are 10.0 moles of beryllium oxide in a 250 grams sample of the compound.
I hope it helps you!
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Oxygen 47 Hydrogen 63
Silicon 28 Oxygen 25.5
Aluminum 7.9 Carbon 9.5
Iron 4.5 Nitrogen 1.4
Calcium 3.5 Calcium 0.31
Sodium 2.5 Phosphorus 0.22
Potassium 2.5 Chlorine 0.03
Magnesium 2.2 Potassium 0.06
Titanium 0.46 Sulfur 0.05
Hydrogen 0.22 Sodium 0.03
Carbon 0.19 Magnesium 0.01
All others <0.1 All others <0.01 Living matter
