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vladimir1956 [14]
2 years ago
15

a model of an atom shows eight electrons in rings that represent different energy levels. how many electrons are in each energy

level?
Chemistry
1 answer:
vlada-n [284]2 years ago
4 0

Answer:

1. four in the first energy level, four in the second energy level

2. eight in the first energy level, zero in the second energy level

3. zero in the first energy level, eight in the second energy level

4. two in the first energy level, six in the second energy level *

Explanation:

1. four in the first energy level, four in the second energy level

2. eight in the first energy level, zero in the second energy level

3. zero in the first energy level, eight in the second energy level

4. two in the first energy level, six in the second energy level *

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science-what kind of input #o you need to provide to make the pen work. Describe the process and out put that result from the in
seropon [69]

Answer:

10 1/3

Explanation:I looked it UP

3 0
3 years ago
19.3 g of cadmium hydroxide reacted with 15.21 g of hydrobromic acid. How many grams of water can be made?
Alecsey [184]

Answer:

m_{H_2O}=3.384gH_2O

Explanation:

Hello,

In this case, the chemical reaction is:

Cd(OH)_2+2HBr\rightarrow CdBr_2+2H_2O

Thus, we first identify the limiting reactant by computing the yielded moles of water by both of the reactants:

n_{H_2O}^{by\ Cd(OH)_2}=19.3gCd(OH)_2*\frac{1molCd(OH)_2}{146.4gCd(OH)_2}*\frac{2molH_2O}{1molCd(OH)_2}=0.264molH_2O\\\\n_{H_2O}^{by\ HBr}=15.21gHBr*\frac{1molHBr}{80.9gHBr}*\frac{2molH_2O}{2molHBr}=0.188molH_2O

In such a way, since HBr yields less water than cadmium hydroxide, we infer that HBr is the limiting one, therefore, the yielded mass of water are:

m_{H_2O}=0.188molH_2O*\frac{18gH_2O}{1molH_2O}\\ \\m_{H_2O}=3.384gH_2O

Regards.

4 0
3 years ago
At a given temperature, the elementary reaction A --->B in the forward direction is first order in A with a rate constant of
Pani-rosa [81]

Answer:

The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.

The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.

Explanation:

For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1}   }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

K'c=\frac{1}{Kc} =\frac{1}{1.72 \times 10^{3}  } =5.81 \times 10^{-4}

4 0
3 years ago
How are sunspots correlated with the sun's activity?
amm1812

Answer:

If sunspots are active, more solar flares will result creating an increase in geomagnetic storm activity for Earth.

Explanation:

I ask mom

8 0
2 years ago
What is the theoretical yield of Ca(OH)2, in grams, if 31.8 g of CaO is hydrolyzed (reacted) in an excess of water?
Fiesta28 [93]

The theoretical yield of Ca(OH)₂ : 42.032 g

<h3>Further explanation</h3>

Given

31.8 g of CaO

Required

The theoretical yield of Ca(OH)₂

Solution

Reaction

CaO + H₂O⇒Ca(OH)₂

mol CaO (MW=56 g/mol) :

= mass : MW

= 31.8 g : 56 g/mol

= 0.568

From equation, mol Ca(OH)₂ = mol CaO = 0.568

Mass Ca(OH)₂ (MW=74 g/mol) :

= 0.568 x 74

= 42.032 g

6 0
3 years ago
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