Answer:
B.) f(x) = 3(4)x − 1
Step-by-step explanation:
A) f(x) = 12(4)x
B.) f(x) = 3(4)x − 1
C.) f(x) = 4(12)x
D.) f(x) = 4(3)x − 1
Given:
f(x+1) = 4f(x)
f(2)=12
f(2) = 12
f(3) = 4f(2) = 4 * 12 = 48
f(3)=48 and f(2)=12
From f(3)=48 and f(2)=12
r=48/12
=4
r=common ratio
Recall,
f(2)=12=ar
r=4
f(2)=ar=12
a*4=12
a=12/4
a=3
an=ar^(n-1)
For x term
an=3*4(x-1)
B.) f(x) = 3(4)x − 1
The circumference of a circle with radius
is

So, one quarter of a circumference will be

You radius is 6, so we have

is the result of multiplying (3x-1) to the second power and (x+6) to the second power
<h3><u>Solution:</u></h3>
Given that we have to find the result of multiplying polynomials (3x-1) to the second power and (x+6) to the second power
"Second power" means the term is raised to power of 2
Therefore,
We have to multiply 

We can use the algebraic identity to expand the above expression

Applying these in above expression, we get

Multiply each term in first bracket with each term in second bracket

Simplify the above expression

Combine the like terms

Thus the above expression is the result of multiplying (3x-1) to the second power and (x+6) to the second power
Answer:
Divide the whole equation by (1 + r)ⁿ to get P = A/(1 + r)ⁿ.