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lisabon 2012 [21]
3 years ago
8

0.371, the digit 7 How do you do this?

Mathematics
2 answers:
Contact [7]3 years ago
7 0

Answer:

digit 7 is in the hundredths place

Step-by-step explanation:

see attached.

goldenfox [79]3 years ago
5 0

Answer:

this doesn't make sense

Step-by-step explanation:

i'm not sure what you are asking

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DOES ANYONE KNOW HOW TO DO THIS PROBLEM???? I AM NOT SURE HOW TO SOLVE THIS PROBLEM!!!!!!!!!!!!!!!!!
Arisa [49]

option 2

option 3

option 1

Hope this helps ^^

4 0
4 years ago
Sebastian writes the recursive formula f(x+1) = 4f(x) to represent a geometric sequence whose second term is 12. Which explicit
NeX [460]

Answer:

B.) f(x) = 3(4)x − 1

Step-by-step explanation:

A) f(x) = 12(4)x

B.) f(x) = 3(4)x − 1

C.) f(x) = 4(12)x

D.) f(x) = 4(3)x − 1

Given:

f(x+1) = 4f(x)

f(2)=12

f(2) = 12

f(3) = 4f(2) = 4 * 12 = 48

f(3)=48 and f(2)=12

From f(3)=48 and f(2)=12

r=48/12

=4

r=common ratio

Recall,

f(2)=12=ar

r=4

f(2)=ar=12

a*4=12

a=12/4

a=3

an=ar^(n-1)

For x term

an=3*4(x-1)

B.) f(x) = 3(4)x − 1

5 0
4 years ago
#81 please!!!!!! I’ll rate you!
natta225 [31]

The circumference of a circle with radius r is

C=2\pi r

So, one quarter of a circumference will be

\dfrac{C}{4}=\dfrac{\pi r}{2}

You radius is 6, so we have

\dfrac{C}{4}=\dfrac{6\pi}{2}=3\pi \approx 9.42

6 0
4 years ago
What’s the answer of a multiplying polynomials (3x-1) to the second power and (x+6) to the second power
Vladimir [108]

9x^4+102x^3+253x^2-204x+36 is the result of multiplying (3x-1) to the second power and (x+6) to the second power

<h3><u>Solution:</u></h3>

Given that we have to find the result of multiplying polynomials (3x-1) to the second power and (x+6) to the second power

"Second power" means the term is raised to power of 2

Therefore,

We have to multiply (3x-1)^2 \text{ and }(x+6)^2

\rightarrow (3x-1)^2 \times (x+6)^2

We can use the algebraic identity to expand the above expression

(a+b)^2 = a^2+2ab+b^2\\\\(a-b)^2=a^2-2ab+b^2

Applying these in above expression, we get

\rightarrow ((3x)^2-2(3x)(1)+1^2) \times (x^2+2(x)(6)+6^2)\\\\\rightarrow (9x^2-6x+1) \times (x^2+12x+36)

Multiply each term in first bracket with each term in second bracket

\rightarrow 9x^2(x^2)+(9x^2)(12x)+(9x^2)(36)-6x(x^2)-6x(12x)-6x(36) + x^2+12x+36

Simplify the above expression

\rightarrow 9x^4+108x^3+324x^2-6x^3-72x^2-216x+x^2+12x+36

Combine the like terms

\rightarrow 9x^4+102x^3+253x^2-204x+36

Thus the above expression is the result of multiplying (3x-1) to the second power and (x+6) to the second power

4 0
3 years ago
1<br>Make p the subject in the formula A = P(1 + r)"​
Snezhnost [94]

Answer:

Divide the whole equation by (1 + r)ⁿ to get P = A/(1 + r)ⁿ.

7 0
3 years ago
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