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const2013 [10]
3 years ago
14

1Make p the subject in the formula A = P(1 + r)"​

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0

Answer:

Divide the whole equation by (1 + r)ⁿ to get P = A/(1 + r)ⁿ.

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A display case of wallets are marked 32 for $5. If Tim has $80, how many wallets can Tim get? (Assume no tax or other fees.)
Levart [38]
1 wallet= 5/32= 0.15625
Wallets for $80= 0.15625*80=12 wallets
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which pair of points forms line that does no intersect the line that passes through the points (5,7) and (7,7)?
Nuetrik [128]

Answer:

(8, -9), (11, -9)

Step-by-step explanation:

The points (5, 7) and (7, 7) are on a horizontal line in which the y-coordinates of all points are 7. The line has equation y = 7.

For a line to not intersect the line y = 7, it must be parallel to y = 7.

The answer is the pair of points which both have the same y-coordinate, and that y-coordinate is not 7.

From the choices you added to your comments, the only choice with two points with the same y-coordinate is (8, -9) and (11, -9). This is the answer.

Answer: (8, -9), (11, -9)

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Mr. Haley is leaning a ladder against the side of his house to repair the roof.
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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 75 type K batteries and a sample of 46
lorasvet [3.4K]

The decision rule for rejecting the null hypothesis, considering the t-distribution, is of:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is not enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means is of zero, hence:

H_0: \mu_1 - \mu_2 = 0

At the alternative hypothesis, it is tested if there is enough evidence to conclude that the mean voltage for these two types of batteries is different, that is, the subtraction of the sample means different of zero, hence:

H_1: \mu_1 - \mu_2 \neq 0

We have a two-tailed test, as we are testing if the mean is different of a value.

Considering the significance level of 0.05, with 75 + 46 - 2 = 119 df, the critical value for the test is given as follows:

|t| = 1.9801.

Hence the decision rule is:

  • |t| < 1.9801 -> do not reject the null hypothesis.
  • |t| > 1.9801 -> reject the null hypothesis.

More can be learned about the t-distribution in the test of an hypothesis at brainly.com/question/13873630

#SPJ1

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