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vivado [14]
3 years ago
7

Simplify –3 – 1. A. –4 B. 2 C. 5 D. –2

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0
B a negative and a negative is a positive
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10 plus what number equals -4
Georgia [21]

Answer:

10 + x =  - 4 \\  x =  - 4 - 10 \\ x =  - 14

6 0
4 years ago
Read 2 more answers
What does 16/6 equal to as a whole number
Inga [223]
It doesn't. 16/6 = 2 4/6 or 2 2/3
3 0
3 years ago
Jonas builds a snow fort. He tells his friends it is 0.80.80, point, 8 meters tall inside, but he rounded the height to the near
laiz [17]

Answer:

D. 0.77

Step-by-step explanation:

Jonas builds a snow fort. He tells his friends it is 0.8 meters tall inside, but he rounded the height to the nearest tenth. Which could be the height of the snow fort before Jonas rounded it?

Check all options by rounding to the nearest tenth

A. 0.89 m

= 0.9 m

B. 0.74 m

= 0.7 m

C. 0.85

= 0.9 m

D. 0.77

= 0.8 m

Note: Digits 0 - 4 are rounded down while digits 5 - 9 are rounded up

Rounding to the nearest tenth means having one digits after the decimal point

5 0
3 years ago
Solve the given initial-value problem. x' = 1 2 0 1 − 1 2 x, x(0) = 2 7
Ilia_Sergeevich [38]
I'll go out on a limb and guess the system is

\mathbf x'=\begin{bmatrix}\frac12&0\\1&-\frac12\end{bmatrix}\mathbf x

with initial condition \mathbf x(0)=\begin{bmatrix}2&7\end{bmatrix}^\top. The coefficient matrix has eigenvalues \lambda such that

\begin{vmatrix}\frac12-\lambda&0\\1&-\frac12-\lambda\end{vmatrix}=\lambda^2-\dfrac14=0\implies\lambda=\pm\dfrac12

The corresponding eigenvectors \eta are such that

\lambda=\dfrac12\implies\begin{bmatrix}\frac12-\frac12&0\\1&-\frac12-\frac12\end{bmatrix}\eta=\begin{bmatrix}0&0\\1&-1\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}
\implies\eta=\begin{bmatrix}1\\1\end{bmatrix}

\lambda=-\dfrac12\implies\begin{bmatrix}\frac12+\frac12&0\\1&-\frac12+\frac12\end{bmatrix}\eta=\begin{bmatrix}1&0\\1&0\end{bmatrix}\eta=\begin{bmatrix}0\\0\end{bmatrix}
\implies\eta=\begin{bmatrix}0\\1\end{bmatrix}

So the characteristic solution to the ODE system is

\mathbf x(t)=C_1\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+C_2\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}

When t=0, we have

\begin{bmatrix}2\\7\end{bmatrix}=C_1\begin{bmatrix}1\\1\end{bmatrix}+C_2\begin{bmatrix}0\\1\end{bmatrix}=\begin{bmatrix}C_1\\C_1+C_2\end{bmatrix}

from which it follows that C_1=2 and C_2=5, making the particular solution to the IVP

\mathbf x(t)=2\begin{bmatrix}1\\1\end{bmatrix}e^{t/2}+5\begin{bmatrix}0\\1\end{bmatrix}e^{-t/2}

\mathbf x(t)=\begin{bmatrix}2e^{t/2}\\2e^{t/2}+5e^{-t/2}\end{bmatrix}
5 0
4 years ago
18. There are 56 fish in a tank, and each fish is yellow, blue, or black. There are six more yellow fish than blue fish, and fou
Alex73 [517]

Answer:

There are 24 yellow fish

Step-by-step explanation:

Blue: x

Yellow: x + 6

Black: x - 4

x + (x + 6) + (x - 4) = 56

3x + 2 = 56

3x = 54

x = 18

7 0
3 years ago
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