Answer:
c. domain: {-2, 0, 2}, range: {-1, 1, 3}
Step-by-step explanation:
Given:
There are three points on the graph.
Locate the
and
values of the points on the graph.
The points are 
Domain is the set of all possible
values. Here, the
values are -2, 0 and 2.
So, domain is: {-2, 0, 2}.
Range is set of all possible
values. Here, the
values are -1, 1 and 3.
So, range is: {-1, 1, 3}
The linear equality y < 3x + 2 is represented by the graph attached.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
An inequality is the non equal comparison of two or more numbers and variables.
The linear equality y < 3x + 2 is represented by the graph attached.
Find out more on equation at: brainly.com/question/2972832
#SPJ1
Answer:
KL= 63
Step-by-step explanation:
JK=7x+9 , JL=114 , KL=9x+9 ( if the points are on the same line and point J at the end point and K in the middle)
*J_______________________K___________________________L
JL=JK+KL
114=7x+9+9x+9
114-18=16 x
16x=98
x=98/16=6
KL= 9x+9
KL=9(6)+9
KL= 63
Answer:
Step-by-step explanation:
The formula for determining the length of an arc is expressed as
Length of arc = θ/360 × 2πr
Where
θ is the central angle formed at the center of the circle.
r represents the radius of the circle.
π represents a constant whose value is 3.14
From the information given,
r = 21 inches
θ = 25 degrees
Length of arc formed = 25/360 × 2 × 3.14 × 21 = 9.2 inches,
Answer:
see below. The solution is the doubly-shaded area.
Step-by-step explanation:
Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.
Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.