Answer:
Looks like -6
Step-by-step explanation:
<u>Answer- </u>
In tossing four fair dice, the probability of getting at most one 3 is 0.86.
<u>Solution-</u>
The probability of getting at most one 3 is, either getting zero 3 or only one 3.
( ∵ xxxx )
( ∵ 3xxx, x3xx, xx3x, xxx3 )
P(Atmost one 3) = P(A) + P(B) = 0.48 + 0.38 = 0.86
You use division
over 2 or 4 or 3 or 5 or 7 and so on
in this case 2 is good
64 = 2 * 2 * 2 * 2 * 2 * 2 ( use division) = 2^6
16 = 2 * 2 * 2 * 2 = 2^4
number reminder
64 0
32 0
16 0
8 0
4 0
2 0
1 1
so 64 = 2^6 (number of zeros) no reminder
1/3(12x-24)=16
3/1[1/3(12x-24)=16]
12x-24=48
+24 +24
12x=72
12x/12=72/12
X=6