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Inessa [10]
3 years ago
5

Which of the following is most likely the next step in the series.

Mathematics
1 answer:
olga2289 [7]3 years ago
5 0

Answer:

I think a is the answer of this question

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An angle measures 40.2° more than the measure of its complementary angle. What is the measure of each angle?
vampirchik [111]
<h3>Solving for the measurements of Complementary Angles</h3><h3>Answer:</h3>

24.9^{\circ} and 65.1^{\circ}

<h3>Step-by-step explanation:</h3>

Recall that Angles that are complementary to each other add up to 90^{\circ}.

Let a be the measure of the complementary angle.

If an angle is 40.2^{\circ} more than its complementary angle, the measure of that angle is a +40.2. The sum of both angles are expressed a +(a +40.2) but since the have to add to 90 as they are complementary, a +(a +40.2) = 90.

Solving for a:

a +(a +40.2) = 90 \\ a +a +40.2 = 90 \\ 2a +40.2 = 90 \\ 2a +40.2 -40.2 = 90 -40.2 \\ 2a = 49.8 \\ \frac{2a}{2} = \frac{49.8}{2} \\ a = 24.9

Since the other angle measures a +40.2, we can plug in the value of a to find the measure of the angle.

Evaluating a +40.2:

a +40.2 \\ 24.9 +40.2 \\ 65.1

The measure of the angles are 24.9^{\circ} and 65.1^{\circ}

4 0
2 years ago
circle 0 shown below has a radius of 27 inches.find to the nearest tenth of a degree the measure of the angle ,x, that forms are
Irina18 [472]

Answer: 29.7 degrees

Step-by-step explanation:

Good, I can see the diagram now!

First calculate circumference of the circle.

C=2πr

C=2π(27)

C=54π in ==> 360 degrees

54π/14=12.11757

360/12.11757=

29.709=29.7 degrees

8 0
2 years ago
First and Second Street are parallel to each other.
garik1379 [7]
If I did this right, it should be:

1. 130 degrees
2. 50 degrees
3. 130 degrees
4. 50 degrees

Here's hoping I'm right. lol
3 0
3 years ago
What is the vertex of the graph of the function below y=x^2-8x+12
Sever21 [200]
That is the answer Y=x^-8x12, xER
9 0
3 years ago
Read 2 more answers
HELP ME PLEASEEEEEEEEEEEE
nasty-shy [4]
The answer is 0.1

17/10 - 8/5 = 0.1
7 0
3 years ago
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