What is 35.2 written in word form?

Which expression is equivalent to the given expression?

Studentka2010 [4]

Which expression is equivalent to the given expression?

15(12-x)

A. $15*12-x$

hope this help

4 0

3 years ago

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

3 years ago

Write an equation for the line described in standard form with x-intercept 4 and y-intercept 5

stealth61 [152]

Answer:

Equation $( \frac{5}{4}) x + y = 5$ is in the standard dorm.

Step-by-step explanation:

Here, the x - intercept = 4 , so ( 4,0) is a point on the line.

and the y - intercept = 5, so ( 0,5) is a point on the line.

So, the slope of the equation is given as = $\frac{y_2 - y_1}{x_2-x_1 } = \frac{5 -0}{0-4} = -\frac{5}{4}$

Now, the SLOPE INTERCEPT FORM of an equation is :

y = mx + b: here m = slope and b = y- intercept

or, $y =-( \frac{5}{4}) x + 5$

Now, standard form is Ax +By = C

So, the standard form is $( \frac{5}{4}) x + y = 5$

Hence, the above equation $( \frac{5}{4}) x + y = 5$

is in the standard dorm.

4 0

3 years ago

The irregular figure on the left has been decomposed into the figures on the right.

Mrac [35]

The answer would be 3 inches

7 0

3 years ago

Read 2 more answers

PLZ HELP NOW I WILL GIVE BRAINLIEST!

solmaris [256]

Answer:

TSA=6a²

TSA=6*17*17=1734 mm²

Step-by-step explanation:

6 0

3 years ago