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kupik [55]
3 years ago
5

the dimensions of a desktop are such that the length is 5 inches shorter than twice its width what expression describes the area

of the desktop in terms of its width w ? (area of a rectangle=bh)
Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
We know that to compute for the area of a rectangle, we can multiply the values of its length and width. Say we have a width of w, if the length of the desktop is 5 inches shorter than twice its width, then

length = 2(w) - 5 = 2w - 5

Given the dimensions, the area can be expressed as (length)(width) = w(2w-5) units².

Answer: w(2w -5) units²
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MAXImum [283]

Answer:

the overall verical change is down 296 feet

Step-by-step explanation:

-296+140= -156

-156-140=-296

3 0
3 years ago
What is the value of f?
laiz [17]

Answer:

f(1/2) = -2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 8x - 6

f(1/2) is x = 1/2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                    f(1/2) = 8(1/2) - 6
  2. Multiply:                               f(1/2) = 4 - 6
  3. Subtract:                              f(1/2) = -2
5 0
3 years ago
On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be
Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0
3 years ago
(-1/3) (-4-3x)=1/2 Solve for x
polet [3.4K]

Answer:

x=-5/6

Step-by-step explanation:

5 0
3 years ago
Help me to do this question ​
gtnhenbr [62]

Step-by-step explanation:

here is tha answer..hope it helps..mark me as brainliest

4 0
3 years ago
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