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mestny [16]
3 years ago
6

Using the digits 3,4,7 and 8, write the largest possible number in word form, if 3 is in the hundreds place

Mathematics
2 answers:
Bumek [7]3 years ago
6 0
8,374 Is the largest number I can make with 3,4,7,&8
MaRussiya [10]3 years ago
3 0

Largest possible number is in reverse order.

Example, given 2395, the largest number is 9532.

If three is in the hundreds place, we have 4,7 and 8 to fill in X3XX, so

8374 is the largest possible number that satisfy given requirements.


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Is this problem right because I need to know thanks!!
inna [77]

Sadly, the answer to your question is 'No'.  The work written under
the problem on the paper is not correct ... because you tried to do
too much !

You can't combine 'm' terms with 'n' terms or with plain numbers.
They all need to stay separate all the way to the end.

So, actually, your first written line is the answer . . .  <em>7m - 35 + 3n</em>

That's as far as you can go.  You can't combine these terms. Stop there !


8 0
4 years ago
The price of a ring varies jointly with
Alchen [17]

Answer:

d = 27

Step-by-step explanation:

Let price = p

Number of diamonds = d

Weigh of gold = w

Hence,

P α d^1/3w

P = kd^1/3 * w

k = proportionality constant

P = 10000 ; d = 64 ; w = 15

We can obtain the value of k

10000 = k * 64^1/3 * 15

10000 = k * 4 * 15

10000 = 60k

k = 10000 / 60

Hence,

P = (10000/60)*d^(1/3)*g

To find the number of d ; when P = 10500 ; g = 21

10500 = (10000/60)*d^1/3 * 21

10500 = 3500 * d^1/3

10500 / 3500 = d^1/3

3 = d^1/3

3³ = d

27 = d

7 0
3 years ago
The figure above shows a circle with center Cand
Natasha2012 [34]

Answer:

Sum of the areas of two  shaded regions = 100 unit² (Approx.)

Step-by-step explanation:

Given:

Radius of circle = 6 units

Angle of one unshaded area = 160'

Find:

Sum of the areas of two  shaded regions

Computation:

Angle of one shaded area = 180' - 160'

Angle of one unshaded area = 20'

Sum of the areas of two  shaded regions = 2[θ/360][πr²]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(6)²]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(36)]

Sum of the areas of two  shaded regions = 2[160/360][(3.14)(36)]

Sum of the areas of two  shaded regions = [0.888][113.04]

Sum of the areas of two  shaded regions = 100.46

Sum of the areas of two  shaded regions = 100 unit² (Approx.)

3 0
3 years ago
Brainliest to whoever gets it right !
vekshin1

Answer:

$1,700.

Step-by-step explanation:

Since Cándido normally pays $ 875 for bodily injury and property damage insurance, and his insurance company increases premiums by 150% for 1 accident, 200% for 2-3 accidents, and 250% for 4 accidents, to find his premium for the year after he has three accidents to the nearest dollar, the following calculation must be performed:

875 x 200 / 100 = X

875 x 2 = X

1,700 = X

Therefore, his premium for the year after he has three accidents is $1,700.

5 0
3 years ago
Alan is 5 years older than Bob. Bob is twice as old as Cindy. All their ages add up to 20. What are their ages?
Llana [10]
We can use a variable equation to solve this. Let A represent alan's age, B represent bob's age, and C represent Cindy's age. So Bob's age would be Alan's age - 5, or a -5 = B. Then Bob's age would be double Cindy's age, so that means 2 multiplied by Cindy's age = Bob's age, or 2C = B. Your two equations are: 

A - 5 = B
2C = B

Also a third equation that helps is A + B + C = 20.

Finally, here are the ages. 
Alan = 11 years old
Bob = 6 years old
Cindy = 3 years old.

PS: Sorry, I'm not that good at explaining things, but here are the answers
6 0
4 years ago
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