The top portion of this graph would be y = 4
The bottom portion would be y = x - 1
In order to find both of these, we have to look at them separately. Let's start with the flat line between 1 and -1. Since it is between those numbers, we know this one goes on top. We also know that since the line is horizontal, that the equation must be y = the number that it sits at. This is the definition of a horizontal line. Since the line is at 4, we get y = 4.
For the sloped portion, we have to pick two points and find the equation of the line. Let's use (3, 2) and (5, 4). We must start by finding slope (m)
m = (y1 - y2)/(x1 - x2)
m = (4 - 2)(5 - 3)
m = 2/2
m = 1
So we know slope to equal 1. Now we can use a point and slope intercept form to find the y-intercept (b)
y = mx + b
4 = 1(5) + b
4 = 5 + b
-1 = b
Now put them together in an equation for the bottom part: y = x - 1
First you graph it using a graphing calculator, you look at the table of values to find out one point in which y= 0. The first one that comes up is when x=1.
If you don't have a graphing calculator you can use trial and error by inputing some numbers into x until you get y= 0.
Once you have an x value which makes y=0, you can start factorizing it.
you divide 6x3 +4x2 -6x - 4 into (x-1) which is when y =0
to get 6x2+10x+4
This can be used to write the polynomial as (x-1)(6x2 +10x+4)
you then factorize the second bracket, 6x2 +10x+4.
you can take the 2 outside to give you 2(3x2 +5x+2)
you can factorize this to become 2(3x+2)(x+1)
Now you just substitute your factorized second bracket into your unfactorized second bracket to give you 2(3x+2)(x+1)(x-1).
From this you can deduce that k= 1
Answer:
I don't know..............
30+3
11*3
10*3+3
60-30+3
(sorry if these didn't help i'm a beginner and i'm in 7th grade)
Zero.
Anything times zero is zero.
-20 * -10 = 200
200 * -1 = -200
-200 * 0 = 0
