The equation for height as a function of time is:
height = (0.5)(acceleration)(time)^2 + (initial velocity)(time) + (initial height)
In this case, x will be the time, so 80 fits the initial height from which the parachute is dropped (the first choice).
The initial velocity of the parachute is 16, while acceleration is -32 (units of length are probably in ft).
Answer:
x+6+x+5=7
Step-by-step explanation:
Answer:
baddie uwu
Step-by-step explanation:
harder daddy harder
Answer:
10.50°C
Step-by-step explanation:
Given x = 2 + t , y = 1 + 1/2t where x and y are measured in centimeters. Also, the temperature function satisfies Tx(2, 2) = 9 and Ty(2, 2) = 3
The rate of change in temperature of the bug path can be expressed using the composite formula:
dT/dt = Tx(dx/dt) + Ty(dy/dt)
If x = 2+t; dx/dt = 1
If y = 1+12t; dy/dt = 1/2
Substituting the parameters gotten into dT/dt we will have;
dT/dt = 9(1)+3(1/2)
dT/dt = 9+1.5
dT/dt = 10.50°C/s
Hence the rate at which the temperature is rising along the bug's path is 10.50°C/s
