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Harman [31]
3 years ago
8

What value of w solves the equation? w^-3 = 1/64 w=___

Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
w^{-3}= \frac{1}{64} \\ \frac{1}{w^3} = \frac{1}{64} \\ w^3=64 \\ w= \sqrt[3]{64}\\ w= \sqrt[3]{4^3}  \\ w=4
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Answer:

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Step-by-step explanation:

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Answer:

1. No.

2. Yes, there is no solution here.

Step-by-step explanation:

The former:

8(5x - 3) = 6(-3x - 4); \\ 8 * 5x - 8 * 3 = 6 * (-3x) - 6 * 4; \\ 40x - 24 = -18x - 24; \\ 40x + 18x = -24 + 24; \\ 58x = 0; \\ x = 0.

\{0\} is our set of solutions.

The latter:

3x - 13 = 7(x + 2) - 4(x - 7); \\ 3x - 13 = 7x + 7 * 2 - 4x - 4 * (-7); \\ 3x - 13 = 7x + 14 - 4x + 28; \\ 7x - 4x - 3x = -13 - 14 - 28;\\ 0x = 55; \\ x \in \emptyset.

In other words, there is not any solution from the set of real numbers that suits us.

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mestny [16]

Answer:

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Red

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