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Harman [31]
3 years ago
8

What value of w solves the equation? w^-3 = 1/64 w=___

Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
w^{-3}= \frac{1}{64} \\ \frac{1}{w^3} = \frac{1}{64} \\ w^3=64 \\ w= \sqrt[3]{64}\\ w= \sqrt[3]{4^3}  \\ w=4
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The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

<h3>How to define the function behind a sequence</h3>

Sequences are sets of elements characterized by at least a rule. In this case, the sequence shown is characterized by a function that generates even numbers equal or greater than 10. The function behind the sequence is shown below:

s = 10 + 2 · (n - 1)     (1)

Where n is the <em>element</em> index.

The sequence shown is defined by a function that generates <em>even</em> numbers equal or greater than 10, defined by the function s = 10 + 2 · (n - 1).

To learn more on sequences: brainly.com/question/21961097

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