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Setler79 [48]
3 years ago
5

Please help me! Show me how you found the answers. 3 ANSWERS NEEDED

Mathematics
1 answer:
boyakko [2]3 years ago
7 0

Answer:

B,C,E

Step-by-step explanation:

Multiple each sales total by .1 and then add 150. If they equal then it works, if they don't then it doesn't. No other way I can think of to explain this.

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The heights of all the newborns in a certain country are normally distributed,
viva [34]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Describe the y-intercept and end behavior of the following graph
lara [203]

Answer:

C

Step-by-step explanation:

y intercept is -8 and it appears as though it is approaching y= -9 to the left.

4 0
4 years ago
The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia
sveta [45]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Technician __Shutdown

Taylor, T___4

Rousche, R _ 3

Hurley, H__ 3

Huang, Hu___2

Gupta, ___ 5

The Numbe of samples of 2 possible from the 5 technicians :

We use combination :

nCr = n! ÷ (n-r)!r!

5C2 = 5!(3!)2!

5C2 = (5*4)/2 = 10

POSSIBLE COMBINATIONS :

TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG

Sample means :

TR = (4+3)/2 = 3.5

TH = (4+3)/2 = 3.5

THu = (4+2) = 6/2 = 3

TG = (4 + 5) = 9/2 = 4.5

RH = (3+3) = 6/2 = 3

RHu = (3+2) /2 = 2.5

RG = (3 + 5) = 8/2 = 4

HHu = (3+2) = 2.5

HG = (3+5) = 8/2 = 4

HuG = (2+5) / 2 = 3.5

Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4

Population mean :

(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4

Population Mean and mean of sample means are the same.

This distribution should be approximately normal.

7 0
3 years ago
5y + 6 = 25 + 6 what property of equality is used
steposvetlana [31]
Addition property
6=6 then 5y+6=25+6
7 0
2 years ago
What is implicit differentiation?
defon

Answer:

The process of finding the derivative of dependent variable in an implicit function by differentiating each term separately by expressing the derivative of the dependent variable as a symbol and by solving the resulting expression for the symbol.


6 0
3 years ago
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