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3 years ago

What are some steps you might take after coming to a solution?

2 answers:

6 0

Answers – A and C
Answering a question does not stop at coming to the solution of a mathematical equation. After coming to a solution, some steps still have to be taken. For instance, you may want to double-check that your answer satisfies the equation and very importantly, present your answer with units. <span>
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konstantin123 [22]3 years ago

6 0

Answer:

i did it and got it right on edenuity so the answers are b,c,e,and f

Step-by-step explanation:

hope this helps and trust me it works 100% on edenuity

why did you come down here its piontless you wasted your time coming down here

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Write (3 ten thousands 4 hundreds) x10

umka2103 [35]

30400x10 that's the answer

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3 years ago

What's greater then 3/8 or 2/4

iVinArrow [24]

Convert 2/4 to 4/8 and then look at the numerators. since 4 is greater than 3, 2/4 is greater than 3/8

7 0

3 years ago

Read 2 more answers

What is the answer with work please

frozen [14]

For 12, the answer would be Y is greater than or equal to 8. If you subtract 193 from both sides of the inequality, you are left with y and 201-193=8. So the overall inequality would look like y>=8. Therefore, you would shade from 8, and everything greater than 8, with a closed circle.

6 0

3 years ago

Urgent!! Will mark brainliest!!

horsena [70]

Answer:

1) x is negative and y is positive ⇒ last answer

2) cotФ = -12/35 ⇒ second answer

3) The right identity is cot²Ф - csc²Ф = -1 ⇒ last answer

Step-by-step explanation:

* For any point (x , y) lies on the terminal side of the angle Ф

in standard position

* x = cosФ and y = sinФ

- If Ф in the first quadrant, then x , y are positive

∴ All trigonometry functions are positive

- If Ф in the second quadrant, then x is negative , y is positive

∴ sinФ only is positive

- If Ф in the third quadrant, then x is negative , y is negative

∴ tanФ only is positive

- If Ф in the fourth quadrant, then x is positive , y is negative

∴ cosФ only is positive

* Lets solve the problems

∵ Ф = 3π/4 ⇒ (135°)

∴ It lies on the second quadrant

∴ x is negative and y is positive

* Lets revise the reciprocal of sinФ, cosФ and tanФ

- cscФ = 1/sinФ

- secФ = 1/cosФ

- cotФ = 1/tanФ

∵ secФ = -37/12

∴ cosФ = -12/37

∵ π/2 < Ф < π

∴ Ф lies on the second quadrant

∴ cotФ is negative values

∵ tan²Ф = sec²Ф - 1

∵ secФ = -37/12

∴ tan²Ф = (-37/12)² - 1 = 1225/144 ⇒ take√ for both sides

∴ tanФ = ± 35/12

∵ cotФ = ± 12/35

∵ cotФ is negative value

∴ cotФ = -12/35

* In the standard position of the angle Ф the terminal

of it lies on the unit circle O

- By using Pythagorean theorem

∵ x² + y² = 1

∵ x = cosФ and y = sinФ

∴ cos²Ф + sin²Ф = 1 ⇒ (1)

∴ cos²Ф = 1 - sin²Ф

∴ sin²Ф = 1 - cos²Ф

* Divide (1) by cos²Ф

∴ cos²Ф/cos²Ф + sin²Ф/cos²Ф = 1/cos²Ф

* Remember sin²Ф/cos²Ф = tan²Ф and 1/cos²Ф = sec²Ф

∴ 1 + tan²Ф = sec²Ф ⇒ (2) ⇒ subtract 1 from both sides

∴ tan²Ф = sec²Ф - 1 ⇒ subtract sec²Ф from both sides

∴ tan²Ф - sec²Ф = -1

* Divide (1) by sin²Ф

∴ cos²Ф/sin²Ф + sin²Ф/si²Ф = 1/sin²Ф

* Remember cos²Ф/sin²Ф = cot²Ф and 1/sin²Ф = csc²Ф

∴ cot²Ф + 1 = csc²Ф ⇒ (3) ⇒ subtract 1 from both sides

∴ cot²Ф = csc²Ф - 1 ⇒ subtract csc²Ф from both sides

∴ cot²Ф - csc²Ф = -1

* The right identity is cot²Ф - csc²Ф = -1

3 0

4 years ago

Sides AB and DC of the rectangle are increased in length by 50% and sides AD and BC are decreased in length by 50%. What is the

emmainna [20.7K]

The percentage of change in the area of the rectangle is -25% ⇒ B

Step-by-step explanation:

The given is:

Sides AB and DC of the rectangle are increased in length by 50%
Sides AD and BC are decreased in length by 50%

We need to find the percentage change in the <em>AREA</em> of the rectangle

Assume that the length of AB ans DC is x units, and the length of AD and BC is y units

∵ The length of the sides AB and DC increased by 50%

∵ The length of AB and CD = x

- That means x will increase by 50% of x

∵ 50% of x = (50 ÷ 100) × x = 0.5 x

∴ The length is increased by 0.5 x

∴ The new length of AB and CD = x + 0.5 x = 1.5 x units

∵ The length of the sides BC and AD decreased by 50%

∵ The length of BC and AD = y

- That means y will decrease by 50% of y

∵ 50% of y = (50 ÷ 100) × y = 0.5 y

∴ The length is decreased by 0.5 y

∴ The new length of BC and AD = y - 0.5 y = 0.5 y units

∵ The area before the change = x × y = xy units²

∵ The area after the change = 1.5 x × 0.5 y = 0.75 xy units²

∵ The new area is less than the old area

∴ The area is decreased

- To find the the percentage of change in the area subtract the

new area from the old area and divide the difference by the

old area and then multiply the quotient by 100%

∴ The percentage of the change = $\frac{xy-0.75xy}{xy}$ × 100%

∴ The percentage of the change = $\frac{0.25xy}{xy}$ × 100%

∴ The percentage of the change = 0.25 × 100%

∴ The percentage of the change = 25%

∴ The area of the rectangle is decreased by 25% ⇒ (-25%)

The percentage of change in the area of the rectangle is -25%

Learn more:

You can learn more about the percentage in brainly.com/question/12960754

#LearnwithBrainly

7 0

4 years ago