The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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Answer
x = 150
Explanation
Based on the given conditions, formulate:
Rearrange unknown terms to the left side of the equation:
Combine like terms:
Divide both sides of the equation by the coefficient of variable:
Remove the parentheses:
Calculate the product or quotient:
Answer: x = 150
Remember that the quadratic formula is:
.
stands for the coefficient of the first term, the one associated with the
,
stands for the coefficient of the second term, the one associated with
, and
stands for the value of the constant.
In
, our a-value is 1, our b-value is also 1, and our c-value is also 1.
Thus, when we plug in our values into our formula, we get the answer:

Simplifying this answer using
, we get our final answer of:

Answer:
n+1
Step-by-step explanation:
justt do ur calculation
Answer:
Step-by-step explanation: