Answer:
72 ft
Step-by-step explanation:
Here, we want to get the maximum height the ball will reach
the maximum height the ball will reach is equal to the y-coordinate of the vertex of the equation
So we need firstly, the vertex of the given quadratic equation
The vertex can be obtained by the use of plot of the graph
By doing this, we have it that the vertex is at the point (3,72)
Thus, we can conclude that the maximum height the ball can reach is 72 ft
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.
Answer:
29.5 inches squared
Step-by-step explanation:
The formula for the area of a trapezoid is ,
so base1 = 14 inches and base2 = 30 inches
since there is a right angle, you know that the height must equal the length of the left side, so the height = 15 inches
then, 14+30+15=59 and 59/2=29.5
therefore, your answer would be 29.5 inches squared