Question

One faucet fills up a bathtub in 15 minutes while the second fills it up in 10 minutes. If both faucets are turned on, what fraction of the bathtub will be filled in 1 minute?

Answer 1

Faucet one fills up $\frac{1}{15}$ of the bathtub in one minute and faucet two fills up $\frac{1}{10}$ of the bathtub in one minute. If both are one then they will fill up  $\frac{1}{15}+ \frac{1}{10} = \frac{5}{30} = \frac{1}{6}$ So, 1/6 of the bathtub in one minute. 

Answer 2

Answer:

Both the faucets will fill 1/6th part of the bathtub.

Step-by-step explanation:

This question can be solved with help of unitary method, means we will calculate the fraction of the bathtub filled by both the faucets individually then by adding their fractions.

∵ 15 minutes have been taken by one faucet is = 1 bathtub.

∴ in 1 minute the fraction of tub can be filled = 1/15 part of full bathtub

Similarly for the second faucet

∵ 10 minutes have been taken by second faucet is = 1 bathtub

∴ in 1 minute the fraction of bathtub will be filled = 1/10 part of bathtub.

Now we will add them to get the fraction of bathtub filled by both the faucets in one minute.

= 1/10 + 1/15= $\frac{(3 + 2)}{30}=\frac{5}{30}=\frac{1}{6}$

Therefore 1/6th part of the bathtub will be filled in 1 minute by both the faucets.