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3 years ago

Whens my birthday sept 18 oct 16 jan 3 feb 14

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

Answer:

I'm going to guess that it is January 3rd. Happy birthday, late or early, by the way! :)

Step-by-step explanation:

FinnZ [79.3K]3 years ago

6 0

Well mines one of those days so imma say Sept 18 and maybe we twins

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The system shown has _____ solution(s).

loris [4]

This system has one solution. Here are my steps to solving this problem:

y=x+1

2(x+1) - x = 2

2x +2 - x = 2

2x - x + 2 = 2

x + 2 = 2
- 2 - 2
----------------
x = 0

y = 0 + 1
y = 1

I hope this helps you!

5 0

4 years ago

Read 2 more answers

‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️Please please help! I’ve been waiting for 30 minutes and still no one has helped!

Alex777 [14]

PART ;

......Circle A.................
Circumference - 2 pi r
25.12 = 2pi(4)
25.12 = 8i
Divide both sides by 8!!
3.14=pi

...Circle B.....................
Circumference = 2 pi r
9.42 = 2pi(3/2)
9.42 = 3pi
Divide both sides by 3!!!
3.14 = pi

PART B

.............Circle A...............
A=pi r ^2
50.24 = pi(4)^2
50.24=16pi
Divide both sides by 16!!!
3.14=pi

.............Circle B.............
A=pi r^2
7.065=pi(3/2)^2
7.065= 9pi/4
Divide both sides by 9/4!!!
3.14=pi

PART C

They used exactly 3.14 for the value of pi in CIRCLE A and B to get the circumference and the area :D

I hope this makes sense!!!
When I wrote 'pi', it was supposed to be the symbol for pi.

5 0

3 years ago

I need help with this question

Julli [10]

Answer:

it's 324

Step-by-step explanation:

divide 72 by 4 to get one side, then multiply the side by itself, 18 times 18

3 0

3 years ago

Consider the markings on the triangles. Which congruence theorem could be used to prove that the two triangles are congruent? Ex

aleksley [76]

The congruent means Exactly equal in size and shape. Congruent sides or segments have the exact same length. Congruent angles have the exact same measure. For any set of congruent geometric figures, corresponding sides, angles, faces, etc. are congruent.

4 0

3 years ago

A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$