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labwork [276]
2 years ago
12

Whens my birthday sept 18 oct 16 jan 3 feb 14

Mathematics
2 answers:
AveGali [126]2 years ago
6 0

Answer:

I'm going to guess that it is January 3rd. Happy birthday, late or early, by the way! :)

Step-by-step explanation:

FinnZ [79.3K]2 years ago
6 0
Well mines one of those days so imma say Sept 18 and maybe we twins
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there are 7 boys and girls in a club. How many different ways to form a queue starting with a girl after each girl?
Soloha48 [4]

Answer:

7 girls can go in the first place, 6 in the second, etc.

7! ways is the number of ways to arrange the girls.

likewise the boys can be arranged in 7! ways

The total number of ways becomes 7! * 7!

7! * 7! = 25,401 600 ways

8 0
2 years ago
ASAP WILL AWARD BRAINLIEST.<br><br> Please find the area of all the shapes.
Mandarinka [93]

Answer:

This a trapezium shape.

8+13/2×4=42 in2

8 0
3 years ago
21 is what percent of 40
-Dominant- [34]
To solve for this, set up a proportion.
21/40 = x/100.
Cross multiply the fraction's numerators with the denominators; 
21 x 100, 40 and x.
2100/40x.
Divide both numbers by 40 to get x.
2100/40 = 52.5
21 is 52.5% of 40.
I hope this helps!
5 0
3 years ago
the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared &lt; X &lt; 1/2( mean + standard deviatio
postnew [5]
The given MGF is that for a random variable following a Poisson distribution with parameter \lambda=3.

This means \mathbb E(X)=\mathbb V(X)=\lambda, and X has PMF

f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}

So, the desired probability is

\mathbb P\left(\lambda-\lambda^2

This is equivalent to

\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232
8 0
3 years ago
Find the amount of simple interest:I=PxRxT<br><br> $1,600 at 3% for 1 year
nirvana33 [79]
I=PRT, P=$1600 R=3% T=1yr
=1600x(3/100)x1
= $48.00
4 0
2 years ago
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