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3 years ago

Do you think the benifits of nuclear power outweigh the potential drawbacks

1 answer:

8 0

More often than not, the pros outweigh the cons when it comes to nuclear energy. It has very low operating costs, produces sufficient energy to meet demand, and has a variety of other economic benefits that can't be ignored

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One advantage to using this form of circuit is that

777dan777 [17]

It has to be the last one because whenever lights are turned on it decreases because all lights are on at the same time. It's good to just have one light on. It doesn't use as much electricity.

8 0

3 years ago

A swimmer is capable of swimming 0.42 m/s in still water. part a if she aims her body directly across a 66-m-wide river whose cu

satela [25.4K]

If the swimmer is swimming perpendicular to the current, it will take her 66m / 0.42 m/s = 157.14 seconds to cross the river. At the same time, the current will be taking her downstream at a rate of 0.32 m/s. So, when she reaches the opposite bank, her total downstream distance traveled will have been 0.32*157.14 = 50.28 meters.

3 0

3 years ago

You are investigating how objects move when they are dropped from different heights. To collect your data, you drop a 1 kg weigh

ASHA 777 [7]

The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

The given parameters;

Mass of the first object, m1 = 1 kg

Mass of the second object, m2 = 5 kg

The final velocity of the objects during the downward motion is calculated as follows;

$v_f = v_0 + gt\\\\v_f = 0 + gt\\\\\v_f = gt$

The time of motion of the object from the given height is calculated as;

$h = v_0 t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} }$

The time of motion of each object is independent of mass of the object.

Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

Learn more about time of motion here: brainly.com/question/2364404

3 0

2 years ago

A 4.5 g coin sliding to the right at 23.8 cm/s makes an elastic head-on collision with a 13.5 g coin that is initially at rest.

Airida [17]

Answer:

a) $v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )$ , b) $\Delta K = 9.559\times 10^{-5}\,J$

Explanation:

a) The final velocity of the 13.5 g coin is found by the Principle of Momentum Conservation:

$(4.5\times 10^{-3}\,kg)\cdot (23.8\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot (0\,\frac{m}{s} ) = (4.5\times 10^{-3}\,kg)\cdot (-11.9\times 10^{-2}\,\frac{m}{s} )+(13.5\times 10^{-3}\,kg})\cdot v$

The final velocity is:

$v = 11.9\times 10^{-2}\,\frac{m}{s} \,(11.9\,\frac{cm}{s} )$

b) The change in the kinetic energy of the 13.5 g coin is:

$\Delta K = \frac{1}{2}\cdot (13.5\times 10^{-3}\,kg)\cdot \left[(11.9\times 10^{-2}\,\frac{m}{s} )^{2}-(0\,\frac{m}{s} )^{2}\right]$

$\Delta K = 9.559\times 10^{-5}\,J$

4 0

3 years ago

Read 2 more answers

Explain why radio and television stations use different frequencies to broadcast programs.

Sedaia [141]

I'm not sure exactly what you're asking.

It could be

==> Why do radio stations use different frequencies from TV stations ?

or it could be

==> Why don't all radio stations, or all TV stations, use the same frequency ?

Radio and TV can't coexist among each other in the same "band"

of frequencies, because they use different amounts of "space" on

the dial. One analog TV channel uses enough dial space for about

600 AM radio stations, or 30 FM radio stations ! That's one click on

the TV channel knob !

So if they were all jumbled up together on the same dial and you

wanted to tune your radio from one AM station to another, you

might have to crank through enough space for 600 radio stations ...

or even 1200 or 1800 of them ... to go to the AM signal you want.

And maybe even worse than that ! I'm sure you've never heard what

a TV signal SOUNDS like on a radio. It is horrendous, and it is loud !

It sounds like a thousand cats shrieking at each other, and it never stops.

That's another good reason to move the TV transmissions to frequencies

where radios will never hear them. If radios just randomly tuned in to a

TV picture signal every now and then, a lot of people would be shocked

out of their socks. They would stop listening to radio, and thousands of

advertisers would not like that.

For the second question ...

OK, so we don't mix radio and TV in the same band of frequencies.

But why does each station need its own frequency ? Why not just

put every radio station on one frequency, and every TV station on

a single frequency that's different from the radio frequency ?

The answer is: It's because people don't want to listen to two radio

stations at the same time, or watch two TV movies at the same time.

We like to make our choice, and then watch them or listen to them

one at a time. And FREQUENCY is the only way our radios and TVs

know how to pick out ONE and ignore all the others.

If there are two, or 5 or 10 stations all on the same frequency within

10 or 20 miles from you, then when you tune your radio to that frequency,

you HEAR two, or 5 or 10, songs, church services, newscasts, political

speeches, or commercials, all at the same time.

So if all radio stations were on the same frequency, or all TV stations

were all on the same frequency, then any time you turned on your

radio or TV, you'd see or hear all of them together. Radio and TV

would completely lose their entertainment value, everybody would

give up watching and listening, and once again ... thousands of

advertisers would not like that.

After all, advertising is the main reason why we have so much radio and TV at all. The advertiser buys, the broadcaster sells, and YOUR eyes and ears are the product.

5 0

3 years ago

Read 2 more answers