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natali 33 [55]
3 years ago
5

Which statement correctly describes the quantitative relationship between acceleration and net force on an object shown in the d

ata table? (1 point) When the net force applied to an object changes, the mass of the object remains constant. When the net force applied to an object changes, the acceleration changes by a different factor. When the net force applied to an object changes, the mass of the object also changes. When the net force applied to an object changes, the acceleration changes by the same factor.

Physics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

The correct answer is A

Explanation:

<h2><u>Because when the net force applied to an object changes, the acceleration changes by the same factor.  This answer is correct and I hope it helps you too.</u></h2><h2><u></u></h2>

Hope this helps....

Have a nice day!!!!

<h2><u></u></h2>
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What does the measurement unit N stand for?
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Explanation:

The newton (symbol: N) is the International System of Units (SI) derived unit of force.

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A car is moving with a constant velocity of 25 m/s. Which of the following is true?
S_A_V [24]

b) the net force on the car is zero.

Explanation:

Let's analyze each option one by one:

a) the force from the engine is greater than all the forces of friction.  --> FALSE. In fact, the car is moving at constant velocity: this means that its acceleration is zero,

a = 0

and so Newton's second law becomes

\sum F = ma = 0

where \sum F is the net force on the car and m is its mass. This means that the net force on the car is zero: so, the force from the engine cannot be greater than all the forces of friction, otherwise the net force cannot be zero.

b) the net force on the car is zero.  --> TRUE, for what we said at point A)

c) the inertia is changing.  --> FALSE. The inertia of an object just depend on the mass and the velocity of the object: as neither the mass nor the velocity are changing in this problem, then the inertia of the car is not changing.

d) the forces of friction are proportional to the acceleration of the car.  --> FALSE. Generally, the force of friction acting on an object moving on a flat surface is

F_f = \mu mg

where \mu is the coefficient of friction, m is the mass, and g the acceleration of gravity. Therefore, the force of friction does not depend on the acceleration of the car.

e) All of the above. --> FALSE

Learn more about net force and Newton's second law:

brainly.com/question/3820012

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3 years ago
Which of the following can lower the activation energy of a system?
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Catalysts
a catalyst is something added to a reaction that speeds it up (or lowers the activation energy)

increasing the temp would speed up the whole reaction but not lower the activation energy
so B.
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I WILL GIVE BRAINLIEST TO THE BEST OR FIRST ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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1 Weather-Weather is the state of the atmosphere, describing for example the degree to which it is hot or cold, wet or dry, calm or stormy, clear or cloudy

2 How much money do you make?

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 a Without the atmosphere, average temperature on Earth would be freezing! Below zero to be exact!

b The atmosphere protects us and animals from dangerous radiation from the Sun. Ultraviolet radiation is basically invisible rays of energy created by the sun.

cAlso, the atmosphere provides oxygen for humans and animals to breathe and C02 (Carbon dioxide) for plants. 

4 warmth 

5 yes it is The water on our Earth today is the same water that’s been here for nearly 5 billion years. Only a tiny bit of it has escaped out into space. As far as we know, new water hasn’t formed either.

That means there’s a very high chance the water in your glass is what thirsty dinosaurs were gulping about 65 million years ago.

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3 years ago
A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh
Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 rad/sec^2

(d) 396.22 revolution

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We have given that diameter d = 1.63 m

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(b) We know that linear speed is given by

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(c) We have given final angular velocity \omega _f=675rev/min

And \omega _i=79.9rev/min

Time t = 63 sec

Angular acceleration is given by \alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2

(d) Change in angle is given by

\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev

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3 years ago
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