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natali 33 [55]
3 years ago
5

Which statement correctly describes the quantitative relationship between acceleration and net force on an object shown in the d

ata table? (1 point) When the net force applied to an object changes, the mass of the object remains constant. When the net force applied to an object changes, the acceleration changes by a different factor. When the net force applied to an object changes, the mass of the object also changes. When the net force applied to an object changes, the acceleration changes by the same factor.

Physics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

The correct answer is A

Explanation:

<h2><u>Because when the net force applied to an object changes, the acceleration changes by the same factor.  This answer is correct and I hope it helps you too.</u></h2><h2><u></u></h2>

Hope this helps....

Have a nice day!!!!

<h2><u></u></h2>
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A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?
Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

                  = 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

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3 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

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Answer:

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