Answer:
B √8
Step-by-step explanation:
Equation of a circle is:
(x − h)² + (y − k)² = r²
where (h, k) is the center and r is the radius.
The center of the circle is (1, 6).
(x − 1)² + (y − 6)² = r²
The circle passes through the point (-1, 8).
(-1 − 1)² + (8 − 6)² = r²
4 + 4 = r²
r = √8
Where is the Image I might can Help
Simplify the following:
(5 i^3 t^4)/7 - 2
i^3 = i^2×i = (-1) i = -i:
(5×-i t^4)/7 - 2
Put each term in (5 (-i) t^4)/7 - 2 over the common denominator 7:
(5 (-i) t^4)/7 - 2 = (-5 i t^4)/7 - 14/7:
(-5 i t^4)/7 - 14/7
(-5 i t^4)/7 - 14/7 = (-5 i t^4 - 14)/7:
Answer: (-5 i t^4 - 14)/7
Answer:
2/3
Step-by-step explanation:
Looking at the graph, it looks like the line goes through (6,10) and (-6,-8). We can "subtract" the points like so:
(6-(-6))/(10-(-8))
=12/18
=2/3
You can remember this trick as "rise over run".
I hope this solution helped you. Happy mathing!
if the diameter is 26 yards, then its radius is half that, or 13 yards.
![\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies C=2\pi (13)\implies C=26\pi \implies C\approx 81.68 \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=13 \end{cases}\implies A=\pi (13)^2\implies A=169\pi \implies A\approx 530.93](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%20%2813%29%5Cimplies%20C%3D26%5Cpi%20%5Cimplies%20C%5Capprox%2081.68%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D13%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2813%29%5E2%5Cimplies%20A%3D169%5Cpi%20%5Cimplies%20A%5Capprox%20530.93)
