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2 years ago

For the function f(x)=-3x+2, find f(2)=

Mathematics

1 answer:

dsp732 years ago

8 0

Answer: f(2) = -4

Step-by-step explanation: Here we're given the function f(x) = -3x + 2 and we are asked to find f(2).

In other words, if we put an <em>x</em> into our function, we get a -3x + 2 out so what happens when we put a 2 into the function?

Well if we put a 2 into the function,

that's f(2) and we get -3(2) + 2 out.

Now all we have to do is simplify on the right side.

-3(2) is -6 so we have -6 + 2 which is -4.

So f(2) is -4.

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Translate the sentence into an equation. Five more than the product of a number and 9 is equal to 6

kap26 [50]

The first thing we will do for this case is to define the following variable:
x = real number.
We then have the following sentence:
"Five more than the product of a number and 9 is equal to 6"
The equation sought is:
9x + 5 = 6
Answer:
An equation for the sentence is:
9x + 5 = 6

6 0

3 years ago

Plz help me 75 points for the 2 questions!!!

liraira [26]

Answer:

<u>The system of equations:</u>

2x + 7y = -11
3x + 5y = -22

Solve by elimination.

<u>Triple the first equation, double the second one, subtract the second from the first and solve for y:</u>

3(2x + 7y) - 2(3x + 5y) = 3(-11) - 2(-22)
6x + 21y - 6x - 10y = -33 + 44
11y = 11
y = 1

2x + 7*1 = -11
2x = -11 - 7
2x = -18
x = -9

<u>The solution is:</u>

x = -9, y = 1

<u>Simplifying in steps:</u>

8u - 29 > -3(3 - 4u)
8u - 29 > - 9 + 12u
12u - 8u < -29 + 9
4u < -20
u < -5

3 0

2 years ago

On a scale drawing with a scale of 1/20, the height of the building is 8 inches. How tall is the actual building in feet?

Alecsey [184]

That means its downgraded to 1/20 of actual height, let actual height is x. Then
(1/20) * x = 8, x = 20 * 8 = 160, actual height = 160 inch
160 inch = 160/12 feet = 13 1/3 feet or 13.333 feet.

3 0

2 years ago

I need to know how to do Solving Systems of Equations by Elimination

vredina [299]

The point of elimination is to have one variable so example

3x + 2y = 4

7X + 3y = 5

1) Try to find a way to have one variable

7(3x + 2y = 4) ----> 21x + 14y = 28

-3(7x+ 3y = 5) -----> -21x -9y = -15

2) add

0 + 5y = 13

3) solve for the last variable

5y = 13
y = 13/5 = 2 3/5 = 2.8

4) Subsitute the variable to get the other one

3x + 2(2.8) = 4

3x + 5.6 = 4

3x = -1.6

x = 0.533333333 (continue)

The intersection would be 0.53 with a line above the 3 and 2.8. (0.5333 , 2.8)

Hope you understand!!

6 0

3 years ago

Solve this x²+8/10 -x = 10/2

AysviL [449]

$x^2+\frac{8}{10}-x=\frac{10}{2}\\
x^2-x+\frac{8}{10}-\frac{10}{2}=0\\
x^2-x+\frac{8}{10}-\frac{50}{10}=0\\
x^2-x-\frac{42}{10}=0\\
x^2-x+\frac{1}{4}-\frac{1}{4}-\frac{42}{10}=0\\
(x-\frac{1}{2})^2=\frac{1}{4}+\frac{42}{10}\\
(x-\frac{1}{2})^2=\frac{5}{20}+\frac{84}{20}\\
(x-\frac{1}{2})^2=\frac{89}{20}\\
x-\frac{1}{2}=\sqrt{\frac{89}{20}} \vee x-\frac{1}{2}=-\sqrt{\frac{89}{20}}\\
x=\frac{1}{2}+\frac{\sqrt{89}}{\sqrt{20}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{\sqrt{20}}\\


$
$x=\frac{1}{2}+\frac{\sqrt{89}}{2\sqrt{5}} \vee x=\frac{1}{2}-\frac{\sqrt{89}}{2\sqrt5}}\\
x=\frac{1}{2}+\frac{\sqrt{445}}{10} \vee x=\frac{1}{2}-\frac{\sqrt{445}}{10}}\\
x=\frac{5+\sqrt{445}}{10} \vee x=\frac{5-\sqrt{445}}{10}}\\$

7 0

3 years ago