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Ivenika [448]
3 years ago
9

The MAX light rail in Portland, OR has a waiting time that is normally distributed with a mean waiting time of 5 minutes with a

standard deviation of 2.9 minutes. A random sample of 40 wait times was selected, what is the probability the sample mean wait time is under 4 minutes? Round answer to 4 decimal places.
Mathematics
1 answer:
Alika [10]3 years ago
5 0

Answer:

34

Step-by-step explanation:

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The ratio of two supplementary angles is 4:5. What are the measures of each angle?
mihalych1998 [28]

Answer:

Step-by-step explanation:

12:15

4 0
3 years ago
Help me for 19 points please thank you
valina [46]

Answer:

Step-by-step explanation:

I hope you dont have to show your work because I am not showing how you do all of those aha.

part 1:

1. p=72, a= 612

2. p=194, a= 32.5

3. p=300, a= 1500

4. p=221, a= 35

and um... I dont know how to do part two. sorry

3 0
3 years ago
Michael plays 1/5 of a song in 1/15 pf a minute. How many minutes will it take to play whole song
mr Goodwill [35]
Well, a whole will be five fifths or 5/5.

now, he only plays 1/5 in 1/15, how many minutes will it take to play the whole 5/5 of the song?

\bf \begin{array}{ccll}
\stackrel{part}{song}&\stackrel{part}{minutes}\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{5}&\frac{1}{15}\\\\
\frac{5}{5}&m
\end{array}\implies \cfrac{\frac{1}{5}}{\frac{5}{5}}=\cfrac{\frac{1}{15}}{m}\implies \cfrac{\frac{1}{5}}{\frac{5}{5}}=\cfrac{\frac{1}{15}}{\frac{m}{1}}\implies \cfrac{1}{5}\cdot \cfrac{5}{5}=\cfrac{1}{15}\cdot \cfrac{1}{m}

\bf \cfrac{1}{5}=\cfrac{1}{15m}\implies 15m=5\implies m=\cfrac{5}{15}\implies m=\stackrel{\textit{minutes}}{\cfrac{1}{3}}
6 0
3 years ago
F - 18 &gt; 92<br><br>I need help fast​
Temka [501]

Answer:

F>110

Step-by-step explanation:

5 0
3 years ago
Parker has a part-time job picking apples. Let the random variable A represent the number of baskets of apples picked each day.
makkiz [27]

Answer:

<u>The correct answer is B. μ = US$87.50 and σ = US$6.50</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of baskets of apples picked each day by Parker = A

Mean of A = 4.5 baskets

Standard deviation = 1.3 baskets

Daily payment received by Parker = US$ 65 + US$ 5 per basket

2. What are the mean μ and standard deviation σ of Parker’s daily pay?

Let's find out the mean and standard deviation of Parker's daily pay:

Daily payment received by Parker = US$ 65 + US$ 5 per basket

Daily payment mean received by Parker = 65 + 5 * 4.5

Daily payment mean received by Parker = 87.5

Standard deviation in US$ = 1.3 * 5

Standard deviation in US$ = 6.5

<u>The correct answer is B. μ = US$87.50 and σ = US$6.50</u>

4 0
3 years ago
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